Latest TCS Aptitude Question SOLUTION: What is the probability of 53 sundays in a leap year ?

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What is the probability of 53 sundays in a leap year ?

Asked In TCS Sravanthitha (9 years ago)

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SUDHAN RAMJEE PETTA  (9 years ago)

A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days.

The remaining 2 days may be any of the following :

(i) Sunday and Monday

(ii) Monday and Tuesday

(iii) Tuesday and Wednesday

(iv) Wednesday and Thursday

(v) Thursday and Friday

(vi) Friday and Saturday

(vii) Saturday and Sunday

For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.

n(S) = 7

n(E) = 2

P(E) = n(E) / n(S) = 2 / 7

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Ramanayya Korada  (9 years ago)

A leap contain 366 days means 52 weeks and 2 odd days.
Those two days may be Saturday and Sunday or Sunday and Monday
A week contain 7 days.
So the probability is:2/7

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Shatakshie Pandey  (9 years ago)

A non leap year contains 364 days i.e. 52 weeks..
A leap year contains 366 days i.e. 52 weeks + 2 days
These 2 days may have combinations like- (Sunday, Monday) ;(Mon, Tue); (Tue, Wed); (Wed, Thurs); (Thurs, Fri); (Fri, Sat); (Sat, Sun)..
So there are Seven possibilities of two days in a leap year..
Therefore probability of getting 53 sundays would be- 2/7

Answer is- 2/7

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Surit Datta  (9 years ago)

2/7 is the probability.

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nitin jangid  (9 years ago)

leap year have 366 days. in this days 52 weeks + 2 days
2 days can{ M T, T W , W TH , TH F ,F S, S SU , SU M}

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kaushik mishra  (9 years ago)

As In a leap year there are 366 days with 52 Sundays in a normal year.so the last day of the leap year combining with other days of the week will be SM,MT,TW,WT,TF,FS,SS where all the letters used are the days of a week..so
Total combination= 7 which is the sample space
And no.of Sundays has 2 combination SM,SS so answer is 2/7

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Sourabh Prasad  (9 years ago)

2/7
Sunday & Monday
Saturday & Sunday

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pranjal dutta  (9 years ago)

366 mod 7 = 2 odd days
2/7 = .285

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Mohan  (8 years ago)

2/7 is the ans..

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