Latest TCS Aptitude Question SOLUTION: the number 272738 and 232342, when divided by n a two digits

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(#M40109385) TCS Numerical Ability question sum of the digits Keep an EYE

the number 272738 and 232342, when divided by n a two digits

Asked In TCS manish singh (9 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

Devendra  (9 years ago)

incomplete question !

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Md Tohosif Ikbal  (7 years ago)

The numbers 272738 and 232342, when divided by n, a two digit number, leave a remainder of 13 and 17 respectively. Find the sum of the digits of n?
a. 7
b. 8
c. 5
d. 4
Explanation:
From the given information, (272738 - 13, 232342 - 17) are exactly divisible by that two digit number.
We have to find the HCF of the given numbers 272725, 232325.
HCF = 25.
So sum of the digits = 7.

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Aritra Ray  (9 years ago)

no..i think we hav to find the sum of the numbers 272738 232342 when divided by 2 digit no..

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patan basheer khan  (9 years ago)

answer is 2
i had done in h.c.m method
dividing greater no with small no and last no i got is 2

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harsha  (7 years ago)

as remainder is 13 & 17 so dividend must be greater than 17

272738 = n*a+13 => 272725=n*a ---(1)
232342 = n*b+17 => 232325=n*b ---(2)

last two digit of (1)&(2) is 25 so n must be 25, no other two digit no. greater than 25 satisfies this

272725=25*10909
232325=25*9293

n=25, sum of digits of n = 2+5 = 7

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