Latest Elitmus Aptitude Question SOLUTION: Q Z F R Q A ------------------ S A X V S W F S X S A X - ---------------------- X X R Q Q V

• Placement Papers
• /
• Elitmus
• /
• Logical Reasoning
• /
• Cryptography

Elitmus Question Papers:

(#M40113881) ELITMUS Logical Reasoning question Cryptarithmetic Keep an EYE

Q Z F
R Q A
------------------
S A X V
S W F S
X S A X
- ----------------------
X X R Q Q V

Asked In Elitmus Ramesh Chakali (9 years ago)

Solved Ashish Read Solution (12)

Is this Puzzle helpful?   (28)   (12) Submit Your Solution Cryptography

Read Solution (12) :

Ashish  (9 years ago) Best Solution

Its very simple.... its clear that S cant be more than 4 as it will lead to a carry which is not feasible...
so start putting values for S=1,2,3,4
For S=1
we can take Q=3 and F=7 or reverse as only multipication of 7 with 3 and 9 with 9 results to unit digit of 1
when s=1, x=2
so we have to take R in a way whose multipication with 7 results in a unit digit of 2 that is possible with 6 only so take R=6
Now here S=1 and X=2 so Q comes as 3
If you proceed with this u will find that addition of X and S is not generating any carry therefore to make unit digit of addition A, F and X as 3 we need to take A as 4
When A=4, V=8
Solve further u will easily get z=5 and w=0

Is this solution Helpfull? Yes (24) | No (1)  

PHANI CHAND TEKKEM  (9 years ago)

hint is to find out that s= 1,2,3,4, bcas we have s+s+carry=x
so by taking s=1 ill start my procedure.
nw we can have carry=0,1,2
so ill start with carry=0
with s=1 and carry=0
1+1+0=> x=2
we have s=1,x=2 now
and we have a hint here that x+s=Q
so 2+1=> Q=3

nowe have s=1 Q=3 x=2

in multiplication it is simple to solve from 2nd row bcas we have repetition of letter S

QZF*Q=SWFS

=>3ZF*3=1WF1
no to get last digit 1 we have to sub F=7

=>3Z7*3=1W71
=> no we must get F=7 on RHS
so go on substituting z=4,5,6...
at z=5 it will satisfy our equation

so => 357*3=1071

itsclear that z=5 and w=0

no we have Q=3, s=1,x=2, Z=5, W=0, F=7



now we have in third column form right hand side that A+F+X=carry+ Q

=>A+7+2=carry+Q
=>9+A=carry+Q
=>to get Q=3 we must have A=4
=>so A=4

now ill take 1st row to get A

QZF*A=SAXV

=> 357*4=142V
=> from this equation to satisfy this we must have v=8

now we have v=8,A=4

now from 4th column from right hand side S+W+A+1(carry)= R
=> 1+0+4+1=6
soR=6

i think i got it now

357
* 634
---------
1428
1071
2142
----------
226338
----------

Is this solution Helpfull? Yes (10) | No (1)  

Ramesh Chakali  (9 years ago)

3 5 7
6 3 4
--------------------
1 4 2 8
1 0 7 1
2 1 4 2
--------------------
2 2 6 3 3 8

Is this solution Helpfull? Yes (7) | No   

Rupen Raj  (9 years ago)

357
*634
---------------
1428
1071
2142
--------------------------
226338

Is this solution Helpfull? Yes (2) | No   

Ashok  (9 years ago)

please explain it

Is this solution Helpfull? Yes (1) | No   

Ehtesham  (9 years ago)

try to find clue..
nd here 2S + Carry= X
now carry, can be 0,1,2;

so, probable values of S=1,2,3,4;
and X=2,3,4,5,6,7,8,9;
now you can easily optimize the value of R,Q,F corresponding to each value of X and S;
lets assume when carry =0;
then S= 1,2,3,4
nd corresponding value of X= 2,4,6,8;

now suppose S=1; then X= 2;
now see the nest clue
R * F=X and
Q * F=S;
now if S =1;then Q=3 or 7 and F=7 or 3 so R=6 or 4;
now proceed with Q = 3,f =7 , R =6;

Q Z F
R Q A
------------------
S A X V
S W F S
X S A X
- ----------------------
X X R Q Q V


then you will find Z must be 5;
now the solution is:

3 5 7
* 6 3 4
---------------------------------
1 4 2 8
1 0 7 1
2 1 4 2
--------------------------
2 2 6 3 3 8

and the worst part is i cudnt solve it in the xam hall..but yes juss after in the bus i crackd it

Is this solution Helpfull? Yes (1) | No   

swati priya  (9 years ago)

s

Is this solution Helpfull? Yes (1) | No   

anshuman  (9 years ago)

do we get options in these type of problems?? plz help...

Is this solution Helpfull? Yes (1) | No   

Pronoy Das  (8 years ago)

S cant be more than 4,SINCE THERE IS NO CARRY(x=x)
now for S=1,X will be 2 and Q=3
NOW
WE HAVE 3ZF*3=1WF1 => so F must be 7

So- 3Z7*3=1W71 by checking we will get Z=5 and W=0
therefore 357*3=1071
now 357*R=21A2 SO must be 6
Hence 357*6=2142(A=4)
so finally-
357
*634
1428
1071
2142
226338

Is this solution Helpfull? Yes (1) | No   

jai pandey  (9 years ago)

357
*634
-------------
1428
1071
2132
--------------
226338

Is this solution Helpfull? Yes | No   

Sanjay Kumar  (8 years ago)

Q#3, Z#5, F#7 , R#6 ,A#4 ,S#1 ,W#0 ,X#2 , V#8.

Is this solution Helpfull? Yes | No   

sagar kumar  (8 years ago)

USE HIT AND TRIAL FOR F & A starting from 2 to 9 hint is
QZF
* Q
------
SWFS
-------
ANS:- 357
*634
-----------------------
1428
1071
2142
---------------
226338

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.