Latest TCS Aptitude Question SOLUTION: If it is a 3x3 matrix, for which elements in first row are (V, 50, W), second row (196, X, Y)and in third row are (269, Z, 123).It is given that the sum of the numbers in each row,

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(#M40115067) TCS Numerical Ability question Keep an EYE

If it is a 3x3 matrix, for which elements
in first row are (V, 50, W), second row (196,
X, Y)and in third row are (269, Z, 123).It is
given that the sum of the numbers in each
row, column, diagonal are same. Then find
the value of (Y + Z).

Asked In TCS shikha (9 years ago)

Solved Abhishek Kumar Read Solution (6)

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Read Solution (6) :

Abhishek Kumar  (9 years ago) Best Solution

Ans : 1122

matrix

v 50 w
196 x y
269 z 123

in 1st row and 1st column
v+196+269=v+50+w
w=415
Again, in 2nd column and 3rd row
50+x+z=269+z+123
x=342

As sum of each row column and diagonal are same.
So, 269+342+415=1026
415+y+123=1026
y=488


269+z+123=1026
z=634

y+z=488+634=1122

Is this solution Helpfull? Yes (31) | No (1)  

umabhargavi  (9 years ago)

v 50 w
196 x y
269 z 123
v+50+w=v+196+269
w=196+269-50
w=465-50=415
similarly
v+x+123=w+x+269
v=415+269-123
v=561
and
so on
ans is 1122

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Prakash kumar  (9 years ago)

ans is.1122

Is this solution Helpfull? Yes (1) | No   

sugata maji  (9 years ago)

Ans : 1122

Is this solution Helpfull? Yes (1) | No   

sumit  (9 years ago)

ans-1122
matrix is
v 50 w
196 x y
269 z 123

then we make a equation x+50+z=269+z+123,
then we get x=342,
same as we get w=415,
from v+342+123=50+v+w,
then we get total of a diagonal 269+x+w=1026,
then we get y=488,from equation w+y+123=1026,
and get z =634,from 269+123+z=1026,

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b  (9 years ago)

v 50 w
196 x y
269 z 123
this is the matrix assume sum is s
by solving v+196+269=s and v+x+123=s
we get x=342
by solving w+y+123=s and w+322+269=s
we get y=468
then cal. sum and cal. z=614
and the ans is y+z is 1082

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