Latest Elitmus Aptitude Question SOLUTION: Teda and meda take two triangles having angles Xt>Yt>Zt and Xm>Ym>Zm respectively. Teda maximizes the angle Xt and Meda Maximizes the angle Ym,Then what is the least value of Xt-Ym

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Teda and meda take two triangles having angles Xt>Yt>Zt and Xm>Ym>Zm respectively. Teda maximizes the angle Xt and Meda Maximizes the angle Ym,Then what is the least value of Xt-Ym.?
(a)2 (b)20 (c)88 (d)none

Asked In Elitmus MOHAMMAD AMIR (9 years ago)

Unsolved Read Solution (4)

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S Suman  (9 years ago)

We will have to limimt ourselves for an integral solution or integral measurement of degrees.
Since, both are going for maximising the angles, the maximum possible angle in a triangle is 178°, the other two being 1° each.
So, as Teda has to maximise X(t), he will choose X(t)=177°, Y(t)=2° and Z(t)=1°.
Similarly, as Meda has to maximise Y(m), he will look for values of Y(m) so that it is just behind of X(m).
So, he will put X(m)=90°,Y(M)=89° and Z(m)=1°.

Therefore, the needed difference = 177° - 89° = 88°.

Hence ,the result would be 88°.

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Siddharth jain  (9 years ago)

ans is 2

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Rajmohan  (9 years ago)

(x+y+z)=180
both teda and meda maximize, any angle value should be equal at maximum of angles therefore least difference will be 0.

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Ehtesham  (9 years ago)

Teda :
xt>yt>zt
now lets see the probable range of xt
90zm
probable range of ym:
2

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