Latest TCS Aptitude Question SOLUTION: What will be the rem.- 1011021030104105............150. divided by 9? option- 0 2 8 4

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What will be the rem.-
1011021030104105............150. divided by 9?
option-
0
2
8
4

Asked In TCS Pranav Bharti (9 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

papolu  (9 years ago)

ans:2 because sum of the terms must be divisible by 9
101+102+103+104+105+....150, n/2*(first term +last term)
50/2*(101+150)
25*251=6275
697*9=6273
rem.=6275-6273=2

Is this solution Helpfull? Yes (16) | No (5)  

Nanditha S  (9 years ago)

if a number is divisible by 9 then sum of its digits should be divisible by 9.
SO now from 101 to 150 the first digit is 1 so the sum is 1+1+....1=50,
And then taking two digits at a time sum of first 50 natural numbers is n(n+1)/2 which gives
50(50+1)/2= 1275 , 1275+50=1325, now 1325%9=2.

if we sum up single digits it gives 380, 380%9=2
so the remainder is 2

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alok ranjan  (9 years ago)

ans is 0
if we add all the digit then divide the sum by 9 then it gives remainder 0

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Ajith Gowda  (9 years ago)

PAPOLU How you got this value 697*9=6273

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IPSITA MAITI  (9 years ago)

101+102+103+104+105+....150, n/2*(first term +last term)
50/2*(101+150)
25*251=6275
6275/9= gives rem 2 so ans.=2

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RAHUL GAUTAM  (9 years ago)

101+102+........+150 mod 9
= 50(101+150)/2 mod 9
= 25*251 mod 9
= (-2)(-1) mod 9 = 2

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Dilip Kumar Meghwal  (9 years ago)

100th digit: 1*50=50
10th digit:1*10+2*10+3*10+4*10+1*5=105
1st digit:(1+2+3+4+5+6+7+8+9)*5=225
Now add all ditits sum=290
Now add 2+9+0=11
11/9=2 Answer

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v  (9 years ago)

ANS : 2
By basic method : {using sum of n number formula }

= (1+2+3+---+150) - (1+2+3+...+100)-.................................................................we get {101+102+.....+150}
= (150*151)/2 - (100*101) /2
= 11325 - 5050
= 6275

6275 divided by 9 and get remainder as 2

> {2}

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