Latest Elitmus Aptitude Question SOLUTION: The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most? Options 1) 1 2) 20 3) 0 4) 19

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(#M40124815) ELITMUS Numerical Ability question problem solving Keep an EYE

The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?

Options
1) 1
2) 20
3) 0
4) 19

Asked In Elitmus k.s.n.kranthi kumar (9 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Pooja Swami  (8 years ago)

At the most 19 numbers can be greater than zero.
Since the 20th number can be equal to the negation of the sum of all 19 numbers .
consider n1, n2, n3....,n19 are all positive numbers and n20 = - (n1+ n2 + ...... n19)
then average = {(n1+ n2 + ..... n19) + (- (n1 + n2 +... n19)) }/ 20
= 0

Is this solution Helpfull? Yes (7) | No (2)  

kundan prasad  (8 years ago)

Ans : 3)0
Sol: let no is X1,X2,X3------------------------------------------X20;
average of those no is
=>(x1+x2+x3+----------------------------------+X20)/20=0
so X1+x2+x3+------------------------------------+x20=0
it possible only when at lest 1 digit should be negative and at most 19 digit should be negative
we put, put X1=19 and X2=X3=X4=-----------------------------------X20=-1
therefore (19-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1)/2-
=(19-19)/20
=0

Is this solution Helpfull? Yes (2) | No   

vivek singhal  (7 years ago)

4) 19 bcoz sum of 19 positive number must be counter balanced by negative number and that number could be equal to sum of 19 positive numbers

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Bimlendu Kumar  (8 years ago)

atmost 19 because...

take any 19 elements +ve add them take 20th element -ve of above sum....
hence avg=0...

Is this solution Helpfull? Yes (1) | No   

ravi prakash  (8 years ago)

option 4) 19

Is this solution Helpfull? Yes | No (2)  

sidhant singh  (8 years ago)

please tell me elitmus 16th result is declare or not?

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PRIYANKA  (7 years ago)

the ans is 19

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Vikash kumar  (7 years ago)

19 is the correct answer

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