Latest TCS Aptitude Question SOLUTION: If n be a odd number greater than 1. than n(n*n-1) will be divisible by................ a)48 b) 24 c)6 d) none of these

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If n be a odd number greater than 1. than n(n*n-1) will be divisible by................ a)48 b) 24 c)6 d) none of these

Asked In TCS souvik das (11 years ago)

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Ratan Lal Jat  (11 years ago)

Odd number just greater than 1 is 3
n(n*n-1)
3(3*3-1)
3(9-1)
3(8)
24
So it is dvisible by both 6 and 24

Is this solution Helpfull? Yes (18) | No (4)  

mohd zubair khan  (11 years ago)

option (d ) is correct
lets check it
on 1 n(n*n-1)= 1(1*0)=0
for 3 =3 (3*2)=18 divisble by 6
for 5 =5 (5 * 4)=100 not divisble by 6
now by option if a number is divisble by 48 means it would be divisble by 24,6 as well
if we take 24 then option c will also be true
thats why we check only for 6 and found not always divisble number so option (d)
is correct

Is this solution Helpfull? Yes (6) | No (35)  

Ratan Lal Jat  (11 years ago)

The answer is 6 and 24

Is this solution Helpfull? Yes (5) | No (2)  

abhishek mishra  (11 years ago)

taking n=7 48,24 and 6 all are answer....i think its a dummy question

Is this solution Helpfull? Yes (3) | No   

rajesh chaparala  (11 years ago)

i think d option will be all of the above not none of these

Is this solution Helpfull? Yes (2) | No (1)  

Adish gupta  (10 years ago)

6 and 24 both
as we can suppose minimum odd no. 3
and we substitute its value in equation
we get 24

Is this solution Helpfull? Yes (1) | No   

Santanu Nandi  (10 years ago)

n(n*n-1)
= n(n^2-1)
=n(n+1)(n-1)
=(n-1)n(n+1)
now n is odd so (n-1)&(n+1) is even..we can get 2*2=4 from it..
and there are three consicutive nos so..one of them is multiple of 3 so we will get one 3 also
all we get two 2's one 3
so it have to be a multiple of 2*2*3=6 (ans)

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Santanu Nandi  (10 years ago)

n(n*n-1)
= n(n^2-1)
=n(n+1)(n-1)
=(n-1)n(n+1)
now n is odd so (n-1)&(n+1) is even..we can get 2*2=4 from it..
and there are three consicutive nos so..one of them is multiple of 3 so we will get one 3 also
all we get two 2's one 3
so it have to be a multiple of 2*2*3=24 (ans)

Is this solution Helpfull? Yes | No   

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