Latest Wipro Aptitude Question SOLUTION: a and b are two numbers selected randomly from 1,2,3.... 25 what is the probability of a and b are not equal. (a) 1/25 (b) 24/25 (c) 13/25 (d) 2/25

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(#M40001479) WIPRO Numerical Ability question Keep an EYE

a and b are two numbers selected randomly from 1,2,3.... 25 what is the probability of a and b are not equal.
(a) 1/25
(b) 24/25
(c) 13/25
(d) 2/25

Asked In Wipro sourav baidya (13 years ago)

Solved sanjeev Read Solution (6)

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Read Solution (6) :

Gunaseelan  (13 years ago)

No of events=625((1,1),(1,2).......(25,25))
Probability of getting a&b are equal=(25/625)[(1,1),(2,2),(3,3).....(25,25)]
Probability of a and b or not equal=1-(25/625)
=600/625
=24/25

Is this solution Helpfull? Yes (54) | No (3)  

sanjeev  (13 years ago)

24/25

a and b are two numbers selected randomly from 1,2,3.... 25.

a can be any number out of 25 numbers.
For b, there are also 25 options from 1 to 25 .
but as according to question b is not equal to a, there are 24 options out of 25.
so the probability of a and b are not equal is 24/25.

Is this solution Helpfull? Yes (20) | No (5)  

Dimple  (13 years ago)

24/25

a and b are two numbers selected randomly from 1,2,3.... 25.

a can be any number out of 25 numbers.
For b, there are 25 options from 1 to 25 .
For and b not equal, there are 24 options out of 25.
so the probability of a and b are not equal is 24/25.

Is this solution Helpfull? Yes (7) | No (3)  

donthulachandrakanth  (13 years ago)

if a and b are to be equally selected frm d numbers then the probability is 1/25
and it is given that the numbers must not be equal then the required probability is =1-1/25=24/25

Is this solution Helpfull? Yes (6) | No (1)  

Amit Nathani  (13 years ago)

we can have 1st no from 1to 25
then we have only 24 option out of 25 for selecting 2nd no
so prob=24/25

Is this solution Helpfull? Yes | No (2)  

Dimple  (13 years ago)

Pls check this qn. How many 4 or 5 digit numbers can be formed by using 0, 1, 3, 5, 8. Repetition is not allowed. None of the given options is correct. No. of 4 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=4*4*3*2=96 No. of 5 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=4*4*3*2*1=96 Total No. of 4 digit or 5 digit nos that can be formed by using 0, 1, 3, 5, 8.( Repetition is not allowed.)=96+96=192

Is this solution Helpfull? Yes | No (10)  

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