Latest IBM Aptitude Question SOLUTION: 4.A company selects an employee at his 25th age and offers salary as Rs.40000 per annum for first 2 years. Afterwards, every year he gets increment of Rs.4000 for next 15 years a

For 1st 2 yrs salary=40,000
After 2 years he get increment of 4000 every year for 15 years
So 15th year salary =44000+14*4000=100000
Now by using arithmetic progression
S15=n/2(a+l)=15/2(44000+100000)=1080000
Now avg salary=80000
80000+10,80000+10,0000x/17+x=80000
By solving
x=10
now 27+15+10=52
so 52 is the age

Employee's salary for first two years = Rs.40,000 (per annum)

So, the total salary for first two years = Rs.80,000 ...(1)

Given that, his salary increased by Rs.4000(per annum) for next 15 years.

So, salary for next 15 years are 44,000, 48,000, 52,000,...
Total salary for next 15 years is 44,000 + 48,000 + 52,000,...

Note that, above sequence is an A.P with first term a = 44000, common difference = d = 4000, total number of terms = n = 15.
We know that, sum of first n terms in A.P = (n/2)[2a+(n-1)d] and nth term = a+(n-1)d
Therefore, 15th term = 44,000+(15-1)4000 = 1,00,000 ...(2)
And the sum of 15 terms = 44,000 + 48,000 + 52,000,+... + 1,00,000
= (15/2)[2x44000 + 14x4000]
= (15/2)(144000) = 10,80,000 ...(3)

From (1) and (3), the total salary of first 17 years = Rs.80,000 + Rs.10,80,000 = Rs. 11,60,000 ...(4)

Form (2), we have, The salary of 17th year = Rs.1,00,000

That is, till his retirement, his salary = Rs.1,00,000 (per annum) ...(5)

Let the employee works for X more years.
Then, the total salary for this X years = Rs.1,00,000 x X

And his experience = 17 + X years ...(5)

Given that, the average salary for 17+X years = Rs.80,000

That is, Rs.80,000 = [Rs. 11,60,000 + RS.1,00,000 x X]/(17+X)
(17+X)80,000 = [11,60,000 + 1,00,000 x X]
(17+X)8 = [116 + 10X]
[136-116] = 10X - 8X
20 = 2X
X = 10

Therefore, from eqn 5, Employee's experience = 17+10 = 27 years.

Since, he hired at his 25th age,his retirement age will be = 25+17 = 42.

Hence, the answer is 42.

Employee's salary for first two years = Rs.40,000 (per annum)

So, the total salary for first two years = Rs.80,000 ...(1)

Given that, his salary increased by Rs.4000(per annum) for next 15 years.

So, salary for next 15 years are 44,000, 48,000, 52,000,...
Total salary for next 15 years is 44,000 + 48,000 + 52,000,...

Note that, above sequence is an A.P with first term a = 44000, common difference = d = 4000, total number of terms = n = 15.
We know that, sum of first n terms in A.P = (n/2)[2a+(n-1)d] and nth term = a+(n-1)d
Therefore, 15th term = 44,000+(15-1)4000 = 1,00,000 ...(2)
And the sum of 15 terms = 44,000 + 48,000 + 52,000,+... + 1,00,000
= (15/2)[2x44000 + 14x4000]
= (15/2)(144000) = 10,80,000 ...(3)

From (1) and (3), the total salary of first 17 years = Rs.80,000 + Rs.10,80,000 = Rs. 11,60,000 ...(4)

Form (2), we have, The salary of 17th year = Rs.1,00,000

That is, till his retirement, his salary = Rs.1,00,000 (per annum) ...(5)

Let the employee works for X more years.
Then, the total salary for this X years = Rs.1,00,000 x X

And his experience = 17 + X years ...(5)

Given that, the average salary for 17+X years = Rs.80,000

That is, Rs.80,000 = [Rs. 11,60,000 + RS.1,00,000 x X]/(17+X)
(17+X)80,000 = [11,60,000 + 1,00,000 x X]
(17+X)8 = [116 + 10X]
[136-116] = 10X - 8X
20 = 2X
X = 10

Therefore, from eqn 5, Employee's experience = 17+10 = 27 years.

Since, he hired at his 25th age,his retirement age will be = 25+27 = 52.

Hence, the answer is 52.

ans is 25th=40,000
till 27th=40,000
28th=44,000
.
.
37th=80,000
so ans is 37 years

Employee's salary for first two years = Rs.40,000 (per annum)

So, the total salary for first two years = Rs.80,000 ...(1)

Given that, his salary increased by Rs.4000(per annum) for next 15 years.

So, salary for next 15 years are 44,000, 48,000, 52,000,...
Total salary for next 15 years is 44,000 + 48,000 + 52,000,...

Note that, above sequence is an A.P with first term a = 44000, common difference = d = 4000, total number of terms = n = 15.
We know that, sum of first n terms in A.P = (n/2)[2a+(n-1)d] and nth term = a+(n-1)d
Therefore, 15th term = 44,000+(15-1)4000 = 1,00,000 ...(2)
And the sum of 15 terms = 44,000 + 48,000 + 52,000,+... + 1,00,000
= (15/2)[2x44000 + 14x4000]
= (15/2)(144000) = 10,80,000 ...(3)

From (1) and (3), the total salary of first 17 years = Rs.80,000 + Rs.10,80,000 = Rs. 11,60,000 ...(4)

Form (2), we have, The salary of 17th year = Rs.1,00,000

That is, till his retirement, his salary = Rs.1,00,000 (per annum) ...(5)

Let the employee works for X more years.
Then, the total salary for this X years = Rs.1,00,000 x X

And his experience = 17 + X years ...(5)

Given that, the average salary for 17+X years = Rs.80,000

That is, Rs.80,000 = [Rs. 11,60,000 + RS.1,00,000 x X]/(17+X)
(17+X)80,000 = [11,60,000 + 1,00,000 x X]
(17+X)8 = [116 + 10X]
[136-116] = 10X - 8X
20 = 2X
X = 10

Therefore, from eqn 5, Employee's experience = 17+10 = 27 years.

Since, he hired at his 25th age,his retirement age will be = 25+27 = 52.

Hence, the answer is 52.

Which i S the crct ans pls tel

its clearly 52 ans

(x-25)*80000=40000*2+40000*15+4000*15+(x-25-15-2)*(40000+4000*15)
x=73

At age of 25,,,salary=40,000
At age of 26,,,,salary=40,000
now for nxt 15 year,,,age will b=26+15+1=42 (1--bcoz he is not retired in 15th year,,job goes on)

answer is : 37 year

5 subjects can be arranged in 6 periods in 6P5 ways.
Remaining 1 period can be arranged in 5P1 ways.
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements = (6P5 x 5P1)/2! = 1800

Alternatively this can be derived using the following approach.
5 subjects can be selected in 5C5 ways.
Remaining 1 subject can be selected in 5C1 ways.
These 6 subjects can be arranged themselves in 6! ways.
Since two subjects are same, we need to divide by 2!
Total number of arrangements = (5C5 × 5C1 × 6!)/2! = 1800

40 000 + 40 000 + (40 000 + 4000) + (40 000 + 2 * 4000) + (40 000 + 3*4000) + ...... + (40 000 + 15*4000) =
80 000 + 15*40 000 + 4000*(15 * (15-1)/2) ) = 1 100 000 = cumulatif salary for 17 years

15 * 4000 + 40 000 = 100 000 = constant salary from 18 year

average = (1 100 000 + x*100 000) / (17+x) = 80 000 => x = 13

age = 25 + 2 + 15 + 13 = 55