Latest Chargebee Aptitude Question SOLUTION: Write a prgm to add sum of the digits of a number,then again sum that and print the output. Example: Sample input:9786456790 Sample output:7

• Placement Papers
• /
• Chargebee
• /
• Programming
• /
• Program

Chargebee Question Papers:

(#M40152075) CHARGEBEE Programming question Programming Keep an EYE

Write a prgm to add sum of the digits of a number,then again sum that and print the output.
Example:
Sample input:9786456790
Sample output:7

Asked In Chargebee Subinraj (8 years ago)

Unsolved Read Solution (17)

Is this Puzzle helpful?   (36)   (7) Submit Your Solution Program

Read Solution (17) :

aman  (8 years ago)

Program in JAVA :

import java.io.*
class solninjava // class name
{
public void main( ) throws IOException //function main used for input
{
BufferedReader std = new BufferedReader(new InputStreamReader(System.in)); //input from console
System.out.print("Enter the Number : ");
int n = Integer.parseInt(std.readLine());
fun(n); // value n send to function fun
}
public void fun(int a) // function fun
{
int s=0; //to store sum of digit
int d;
while(a>0) // it runs till a>0
{
d=n%10;
s=s+d;
a=a/10;
}
if(s>10) // condition if sum is greater then 10
{
fun(s) //then that sum is again send to funtion fun as new number
}
else
{
System.out.println(" Output : "+s); //else print sum as output
}
}
}

Program in PYTHON 2.7.9
"""I have excuted the python program"""

def fun(n):
s=0
while n>0:
d=n%10
s=s+d
n=n/10

if s>10:
fun(s)
else:
print s

no=integer(raw_input("Enter the number : "))
fun(no)

Is this solution Helpfull? Yes (4) | No   

aman  (8 years ago)

Python have different syntax as here curly bracket is presented by white space .... As white space are automatically removed in m4maths solution that why whitespace has been removed from python which plays important role ... If u know python then u know where u need to add white spaces ..... Java program do not need changes ... Logic is same for program in both

Is this solution Helpfull? Yes (1) | No   

aman  (8 years ago)

In java program please correct one thing ...in function fun ...in while loop ....correct d = a%10 ...do like it thankx

Is this solution Helpfull? Yes | No   

Subinraj  (8 years ago)

import java.util.Scanner;

public class Demo4 {
public static void main(String args[])
{
int[] a=new int[10];
int b=0,i,c,d,e;
Scanner sc=new Scanner(System.in);
for(i=0;i

Is this solution Helpfull? Yes | No (1)  

Subinraj  (8 years ago)

import java.util.Scanner;
public class Demo4 {
public static void main(String args[])
{
int[] a=new int[10];
int b=0,i,c,d,e;
Scanner sc=new Scanner(System.in);
for(i=0;i

Is this solution Helpfull? Yes | No (1)  

sandeep  (8 years ago)

#include
int main()
{
long long int n,count,m;
printf("Enter ");
scanf("%lld",&n);

count=n;
while(count%10!=count)
{

n=count;
m=0;
while(n!=0)
{
m=m+n%10;
n=n/10;
}
count=m;
}
printf("%d",m);
return 0;
}

Is this solution Helpfull? Yes | No   

sowmya  (8 years ago)

#include
using namespace std;
int func(int n);
int main()
{
int p,f,i=0,sum=0,k;
coutp;


f=func(p);
if(f>10)
{
f=func(f);
cout

Is this solution Helpfull? Yes | No   

divakar raju  (8 years ago)

Program in Java:

import java.util.Scanner;

public class SumOfNumbers {

private static Scanner scan;

public static void main(String[] args) {
scan = new Scanner(System.in);
System.out.println("Enter the number to be added");
String num = scan.nextLine(); //get input from user as string
long result=0;
while (num.length() > 1) //loop goes till length becomes 1
{
long number=Long.parseLong(num); //converting string to long
long a = 0;
long b=0;
while (number >= 1) //loop goes till number >=1
{
b = number % 10;
a = a + b; //adding digits in given number
number = number / 10;
}
num=Long.toString(a); //again converting it to string to find the length of the digits
result=a; //
}
System.out.println("the sum of numbers is " + result); // printing the result

}

}

Is this solution Helpfull? Yes | No   

vivek  (8 years ago)

#include
int main()
{
long long int n,sum=0,s=0,r,a;
printf("enter the number");
scanf("%lld",&n);
while(sum)
{ r=n%10;
n=n/10;
sum=sum+r;}
while(sum){
a=sum%10;
sum=sum/10;
s=s+a;}
printf("the sum is %lld",s);
return 0;
}

Is this solution Helpfull? Yes | No (1)  

Mathan kumar Mariappan  (8 years ago)

int main(n){
s=0;
while(n>0){
t=n;
while(t>0){
t=t%10;
s=s+t;t=t/10;
}n=s;
}
return(s)

Is this solution Helpfull? Yes | No   

Famitha nelofer B  (8 years ago)

#include
#include
void main()
{
long int sum=0,no;
cin>>no;
getch();
cout

Is this solution Helpfull? Yes | No (1)  

PARAMESWARAN  (8 years ago)

Logic :

Result =number%9

I have done this program in Python

num=int(input())
print(num%9)

Is this solution Helpfull? Yes | No   

PARAMESWARAN  (8 years ago)

Sorry,I have done a mistake in previous solution.

SOLUTION WITH CORRECT LOGIC
num=int(input())
if num > 0 and num % 9 ==0:
print(9)
else:
print(num % 9)


SAMPLE OUTPUT:
INPUT:9999999999
OUTPUT:9
(In previous logic the output will be 0 which is wrong)

Is this solution Helpfull? Yes | No (1)  

sai_1992  (8 years ago)

class Main{
public void main(String args[]{
int num=9786456790;
int result=num%9;
if(result) System.out.println(result);
else System.out.println(9);
}
}

Is this solution Helpfull? Yes | No   

manerethinam.j  (7 years ago)

#include
int n,sum,reminder;
int func(int):
void main()
{
int temp;
printf("enter the any integer number");
scanf("%dt",&n);
temp=n;
func(temp)
}
int func(int t)
{
int j;
while(temp!=0)
{
reminder=temp%10;
sum=sum +reminder;
temp=temp/10;
}
j=sum;
func(j)
printf("sample output:%d",sum)
}

Is this solution Helpfull? Yes | No   

vignesh  (7 years ago)

import java.util.Scanner;

public class Summ {
public static long sum(long n)
{
int rem,sum=0;
while(n!=0)
{
rem=(int) (n%10);
sum=sum+rem;
n=n/10;
}
return sum;
}
public static void main(String args[]){
Scanner s=new Scanner(System.in);
long num=s.nextLong();
int sum=(int) sum(num);
if(sum9)
{
sum=(int) sum(sum);
}
System.out.println(sum);
}
}
}

Is this solution Helpfull? Yes | No   

balaji  (6 years ago)

It's not possible to get such a large value as an integer.
so we should use some other data to get the input.


import java.util.Scanner;
import java.lang.String;

public class MainClass {
public static int digitSum(int num )
{
int sum=0;
while(num>0)
{
sum+=num%10;
num/=10;
}
return sum;
}
public static void main(String []args)
{
String num;
Integer sum=0;
Scanner sc=new Scanner(System.in);
num=sc.next();
for(int i=0;i

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.