Latest Elitmus Aptitude Question SOLUTION: A lady bought five books namely A,B,C,D,E to distribute her 3 child. How many ways she can distribute books?

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(#M40152468) ELITMUS Numerical Ability question p&c Keep an EYE

A lady bought five books namely A,B,C,D,E to distribute her 3 child. How many ways she can distribute books?

Asked In Elitmus NRJ Soni (8 years ago)

Solved Devendra Marghade Read Solution (31)

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Read Solution (31) :

patanjali kumar sharma  (8 years ago)

3^5
3*3*3*3*3

Is this solution Helpfull? Yes (32) | No (5)  

Devendra Marghade  (8 years ago) Best Solution

60

With AB there can be 3 possible combinations ABC, ABD or ABE, so similar 3 combinations are possible with AC, AD and AE, total 3*4=12
Similarly 12 combinations are possible for B, C, D, or E
So total combinations of 3 with Given A,B,C,D,E=5*12=60

Is this solution Helpfull? Yes (21) | No (28)  

Ankita Anand  (8 years ago)

There are 3 children.The first one can get any of the 5 books,the second can get any one of the remaining four books and the third one any of the remaining 3 books.
So the total no of ways is 5*4*3=60.

Is this solution Helpfull? Yes (15) | No (4)  

Abhishek Mohanty  (8 years ago)

3^5.
because no of filling 3 blank spaces with 5 objects is 3^5

Is this solution Helpfull? Yes (8) | No (3)  

pratyaksh  (8 years ago)

Since we have to select any 3 books from 5 books, so here we will use Combination.
5C3(Selecting combination) *3!(Shuffling in selected combination)

so here comes, 5*4*3=60 //Ans.

Is this solution Helpfull? Yes (6) | No   

Subhash Gupta  (8 years ago)

ways to distribute 5 objects to 1 child=3
ways to distribute 5 objects to 2 children=(1,4)+(2,3)=30+60=90
ways to distribute 5 objects to 3 children=(1,1,3)+(1,2,2)=60+90=150
hence total=3+90+150=243

Is this solution Helpfull? Yes (5) | No (9)  

ADITYA AKASH  (8 years ago)

REALLY PUZZLED !!!!!!!!! HOW DEVENDRA MARGHADE GOT BEST SOLUTION........... 110% WRONG

Is this solution Helpfull? Yes (5) | No (9)  

Anjali Sadhukhan  (8 years ago)

if you want to have pure logicc though that will take a big space in your copy :P..so here how it goes..with the letter 'A' all possible combination to the three kids.ABC,ABD,ABE,ACB,ACD,ACE,ADB,ADC,ADE,AEB,AEC,AED ..COUNT how many ways formed here.i.e 12 ways.so this will multiply by 5 .hence 60.multiply by 5 as for the alphabets A,B,C,D,E.

Is this solution Helpfull? Yes (5) | No (6)  

Shruti sneha  (8 years ago)

i dnt knw y ppl submit their solution mere by guessing. its quite shameful. its helping site fr d aspirants. if u dnt knw den plz dnt commnt illogical answers.

Is this solution Helpfull? Yes (5) | No   

sourav kumar  (8 years ago)

3^5.
Because 5 books is distributed to her 3 child.

Is this solution Helpfull? Yes (2) | No (2)  

VISHAL KUMAR  (8 years ago)

Ans. 3^5
The lady can distribute the 1st. book to children in 3 ways since there is no any condition so again she can distribute 2nd book in 3 ways in this way the lady can distribute all books in 3^5 ways.

Is this solution Helpfull? Yes (2) | No (1)  

parul sharma  (8 years ago)

arpit no 2 books are left all r distributed ...in 5c3

Is this solution Helpfull? Yes (2) | No (1)  

jyotsna kumari  (8 years ago)

according to arun sharma
it will be 3^5

Is this solution Helpfull? Yes (2) | No (1)  

NRJ Soni  (8 years ago)

Options are1) 60
2) 168
3)125
4)343
I thought Devendra solution is right

Is this solution Helpfull? Yes (1) | No   

bhagya shri  (8 years ago)

ans :
3^5

Is this solution Helpfull? Yes (1) | No (2)  

Pawan Kumar Tiwari  (8 years ago)

5c3*3! because we have to select 3 things from five and then and the we have to check possible arrangement.

Is this solution Helpfull? Yes (1) | No   

vibha  (8 years ago)

lady can give 5 books to 1st child, 4 to 2nd child, 3 books to 3rd child. so no of ways will be = 5*4*3
=60

Is this solution Helpfull? Yes (1) | No   

Nirmalrajsanjeev  (8 years ago)

Here is 5 types of books A,B,C,D,E.
distributed in 3 children
5c3*3!=
{(5*4*3!)/2!*3!}*3!=60

Is this solution Helpfull? Yes (1) | No   

sunil  (8 years ago)

_____ _____ _____
5 4 3
since no repeation can be so

first place will 5 chances and second place will get 4 (bcz any of one is used so 5-1) same for next (only 3 bcz 4-1)

5*4*3=60

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Ganesh Babu K  (8 years ago)

5p3 = 60.
5 books for 3 child's.

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vishwa  (8 years ago)

5c3* 3! is the correct ans

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smriti kumari  (8 years ago)

5c3 ways !5/!3*!2

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Arpit dubey  (8 years ago)

what about the remaining 2 books ? they should also be distributed because books are not to be distributed equally...

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Tamal Chakraborty  (8 years ago)

Ans: 60.

5P3 = 60

Is this solution Helpfull? Yes | No (1)  

om awasthi  (8 years ago)

n distinct things can be divided in r distinct group in -> r^n ways
so here n=5
r=3
so 3^5 is correct answer
other way we can understand child may be contain 1 or 2 or 3 books
so each book have 3 choice
3*3*3*3*3=3^5 is answer

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shubham pal  (7 years ago)

factorial of 5

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Nidhi Mishra  (7 years ago)

Books can be given to the first child in 5 ways,second child in 4 ways and third child in 3 ways since the repetition is not possible here, otherwise solution should be 5^3.
hence the solution is 5*4*3=60ways.

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Pooja Ghosh  (6 years ago)

There is no restriction on how many books a chiild can get. A child can get either no book or all 5 books.

The first book can be distributed in 3 ways (can be given to any of the child)

Similarly, the second book can be distributed in 3 ways (can be given to any of the child)

.

.

The fifth book can be distributed in 3 ways (can be given to any of the child)

So, total number of ways of distributing 5 books among 3 childrens = 3x3x3x3x3 = 243

Is this solution Helpfull? Yes | No   

SrinivasGupta  (6 years ago)

we can use n+r-1 c r-1 formula here..and the answer is 21

Is this solution Helpfull? Yes | No (1)  

SrinivasGupta  (6 years ago)

"a" is the correct option

Is this solution Helpfull? Yes | No (1)  

Digesh Singh Bisht  (1 year ago)

ans is 60.
Two ways to do this
(i)
(5c3)*3! = 60(by using formula)

(ii)
5*4*3=60 (by using simple logic)

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