Latest igate Aptitude Question SOLUTION: ( 517 X 517 X 517 + 483 X 483 X 483)/(517 X 517 – 517 X 483 + 483 X 483). Find the result of this expression. A. 1 B. 1000 C. 5436948 D. 23,45,683

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(#M40152495) IGATE General Ability question Keep an EYE

( 517 X 517 X 517 + 483 X 483 X 483)/(517 X 517 – 517 X 483 + 483 X 483). Find the result of this
expression.
A. 1
B. 1000
C. 5436948
D. 23,45,683

Asked In igate C Ramya Udaya Chandrika (8 years ago)

Unsolved Read Solution (37)

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Read Solution (37) :

C Ramya Udaya Chandrika  (8 years ago)

B.
Cuz, a3+b3=(a+b)(a2-ab+b2)
so [(a+b)(a2-ab+b2)] / (a2-ab+b2)= a+b=517+483=1000.

Is this solution Helpfull? Yes (50) | No (2)  

shesharaupally jyothi  (8 years ago)

1000: as 517+483

Is this solution Helpfull? Yes (3) | No (1)  

rashmi r m  (8 years ago)

1000
(a^3+b^3)=(a+b)*(a^2+b^2-ab)

Is this solution Helpfull? Yes (1) | No (2)  

Sumit Srivastava  (8 years ago)

(a^3+b^3)/(a^2-a*b+b^2)=a+b

Is this solution Helpfull? Yes (1) | No   

pankaj  (8 years ago)

(a3+b3)/(a2-ab+b2)=a+b
hence , ans=517+483=1000

Is this solution Helpfull? Yes (1) | No   

tejasvini  (8 years ago)

1000
(a3 + b3)/ (a2-ab+b2)=(a+b)
--> = (517+483)=1000

Is this solution Helpfull? Yes (1) | No   

salma  (8 years ago)

A+B=1000
Ans:B

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PraveeNkumar  (8 years ago)

B).1000., By using Vedic Method of multiplication, We get ans as 1000.

Is this solution Helpfull? Yes | No (2)  

Mohammad Husain  (8 years ago)

1000 a3+b3=(a+b)(a2-a*b+b2)

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Harshvardhan kumar  (8 years ago)

(a^3+b^3)/a^2-ab+b^2=a+b=517+483=1000

Is this solution Helpfull? Yes | No (1)  

Raghvendra Pandey  (8 years ago)

a^3+b^3=a^2+b^2-ab
Then a+b=1000

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NIKHIL RANAJN  (8 years ago)

1000 IS THE ANS .USE (A+B)^3

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Rahul Verma  (8 years ago)

B.1000
(a^3+ b^3)/(a^2-ab+ b^2)=a+b

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TARANG VARSHNEY  (8 years ago)

a3+b3=(a+b)(a2+b2-a*b)
1000

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SARTHAK DAS ROY  (8 years ago)

B.
explaination-
a+b=(a^3+b^3)/(a^2-ab+b^2)

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shraddha dabhade  (8 years ago)

a+b = 517+483 =1000

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suraj nath prasad  (8 years ago)

b.1000
as it is of the form (a^3+b^3)/(a^2-a*b+b^3)

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Rashmi Keshri  (8 years ago)

a=517,b=483
a+b=517+483=1000

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Shweta Redekar  (8 years ago)

517+483=1000

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Sufal Ghosh  (8 years ago)

B.1000
as a^3+b^3=(a+b)(a^2-ab+b^2)

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vishnu  (8 years ago)

1ooo this is very simple a^3+b^3=(a+b)(a^2-ab+b^2)

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Monidip Bose  (8 years ago)

a=517,b=483
then it means
(a^3+b^3)/(a^2-ab+b^2)=(a+b)(a^2-ab+b^2)/(a^2-ab+b^2)=a+b
then ans is 517+483=1000

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Aneesh Sawant  (8 years ago)

B.1000
The result of the question according to BODMAS rule

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Ayanendu Banerjee  (8 years ago)

ANSWER B
APPLYING THE ( a^3+b^3) formula

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Sreenidhi  (8 years ago)

10000
a+b=1000

Is this solution Helpfull? Yes | No (1)  

Dinesh Kumat Sathrasala  (8 years ago)

B. 1000
since it is in the form (a^3+b^3)/(a^2-ab+b^2) = a+b
so 517+483 = 1000

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gaurav jangra  (8 years ago)

1000
formula a^3+b^=(a+b)(a^2-ab+b^2) then
517+483=1000

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shubham shivhare  (8 years ago)

its in terms of formula in the numerator and as well as in denominator
numerator= (517x517x517+483x483x483)
(517^3+483^3) = (a^3+b^3) = (a+b) (a^2-ab+b^2)
denominator = (517x517-517x483+483x483) = (a^2-ab+b^2)
therefore , (a^2-ab+b^2) will get cancelled & remaining is (a+b)
which equals 517+483 = 1000.

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Narasimha  (8 years ago)

(a^3+B^3)/(A^2-ab+b^2) = (a+b). so, 517+483 = 1000

Is this solution Helpfull? Yes | No (1)  

Nandkishor jaiswal  (8 years ago)

a^3+b^3=(a+b)(a^2-ab+b^2)
so answer should be (a+b)=517+483=1000

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N Mounika  (8 years ago)

It just look like ((a*a*a)+(b*b*b))/((a*a)-(a*b)+(b*b))-------> a3+b3/(a2-ab+b2)
we know that a3+b3=(a+b)(a2-ab+b2)
so, a+b is our result
i.e; = 517+483-------->1000

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Mahender  (8 years ago)

a^3+b^3=( a+b)(a^2-ab+b^2)
Use above formula

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sudeepa  (8 years ago)

=>(a^3+b^3)/(a^2-ab+b^2)
=>(a+b)(a^2-ab+b^2) / (a^2-ab+b^2)
=>a+b
=>a=517 and b=483 then a+b=1000

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Madhusudhana  (8 years ago)

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khajaprasad vunnam   (8 years ago)

a3+b3=(a+b)(a2-ab+b2)

so answer is a+b=517+483=1000

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N.Vignesh  (8 years ago)

1000 by using a3+b3 formula

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chitrita biswas  (7 years ago)

b.1000
x=517
y=483

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