Latest TCS Aptitude Question SOLUTION: In how many ways 11women and 5 men can be suffeled to get 11 members with atleast 3men?

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In how many ways 11women and 5 men can be suffeled to get 11 members with atleast 3men?

Asked In TCS Sathish kumar (8 years ago)

Unsolved Read Solution (26)

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kondapuram tirumalreddy  (8 years ago)

answer is 3762
atleast 3 men means we need to incude 3 or more men for every group of 11 members.
5c3*11c8+5c4*11c7+5c5*11c6

Is this solution Helpfull? Yes (7) | No   

suchismita garai  (8 years ago)

5c3*11c8+5c4*11c7+5c5*11c6

Is this solution Helpfull? Yes (2) | No   

Chaitanya  (8 years ago)

5c3*11c8+5c4*11c7+5c5*11C6=3762 ways

Is this solution Helpfull? Yes (2) | No   

Sarabeshwar  (8 years ago)

sorry... that should be 10 * 165 = 1650

Is this solution Helpfull? Yes (1) | No   

Sakshi Agarwal  (8 years ago)

16C11 -( 5C0 X 11C11) - (5C1 X 11C10) - ( 5C2 X 11C9) = ANS
first choose all possible combinations (ie. 11 people out of 11+5 people) then subtracting unfavorable cases (ie in which 0men&11 women were selected or 1 men&10 women were selected or 2 men and 9 women were selected)

On solving answer comes to be 3762

Is this solution Helpfull? Yes (1) | No   

IMRAN NAZIR  (8 years ago)

8 women+3 men=11 member. (out of 11 women and 5 men)
7 women +4 men =11 member. (out of 11 women and 5 men)
6 women+5 men=11 member. (out of 11 women and 5 men)
so,(11c8*5c3)+(11c7*5c4)+(11c6*5c5)=3762

Is this solution Helpfull? Yes (1) | No   

Sarabeshwar  (8 years ago)

5c3 + 11c8 = 10 + 165

175

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ashvini kumar  (8 years ago)

total no of ways=5c3*11c8+5c4*11c7+5c5*11c6=3762

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Niraj Kumar Shukla  (8 years ago)

that will be 5c3 * 11c8 + 5c4 * 11c7 + 5c5 * 11c6

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shambhu  (8 years ago)

16c5- (11c11+(11c10*5c1)+(11c4*5c2))

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minu sen  (8 years ago)

plz explain clearly

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Shivani Gola  (8 years ago)

we need 11 members with ATLEAST 3 men so..
(11c11+5c0)+(11c10+5c1)+(11c9+5c2)+(11c8+5c3)=(1+1)+(11+5)+(55+10)+(11*15+10)=258...i think

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kondapuram tirumalreddy  (8 years ago)

answer is 3762
atleast 3 men means we need to incude 3 or more men for every group of 11 members.
5c3*11c8+5c4*11c7+5c5*11c6

Is this solution Helpfull? Yes | No   

Shivani Gola  (8 years ago)

we need 11 members with ATLEAST 3 men so..
(11c11*5c0)+(11c10*5c1)+(11c9*5c2)+(11c8*5c3)=(1*1)+(11*5)+(55*10)+(11*15*10)=2266...i think

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aswinbalamurali  (8 years ago)

11c11+ 11c10*5c1 + 11c9*5c2 + 11c8*5c3

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gulisettyanusha  (8 years ago)

we can select atleast 3 men fromb5 men so 5c3
and we want 11 members so remaining are 8 we take from women as 11c8
then finally 11c8*5c3=19800

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Sandip Shaw  (8 years ago)

in group there has to be 3 men -for this we can select 3 men from 5 in 5c3 ways and remaining 8 from 11 women in 11c3 ways

therefore total ways:- 5c3*11c3

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Oindrila Ghosh  (8 years ago)

5C3 x 11C8 + 5C4 x 11C7 + 5C5 x 11C6
= 3762

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soundarya krishnamurthy  (8 years ago)

11c8*5c3 + 11c7*5c4 + 11c6=3762

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Naresh  (8 years ago)

11 women 5 men ways of selection
8 3 11C8 * 5C3
7 4 11C7 * 5*4
6 5 11C6 * 5C5

Hence no. of selecting is

(11C8 * 5C3)+(11C7 * 5C4)+(11C6 * 5C5) =3762 WAYS

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ayushi parida  (8 years ago)

5c3 * 11c8=1650

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Pooja Sharma  (8 years ago)

16c11- (11c11 + 11c10*5c1 + 11c9*5c2)

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sher singh  (8 years ago)

5c3*11c8+5c4*11c7+5c5*11c6
=3762

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Kanika Rana  (8 years ago)

2442 is theans

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Maitreyi Sutradhar  (8 years ago)

5c3*11c8+5c4*11c7+5c5*11c6

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Robin singh  (8 years ago)

5c3*11c8+5c4*11c7+5c5*11c6=3762

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