Latest TCS Aptitude Question SOLUTION: Find the number of zeroes in the expression 15*32*25*22*40*75*98*112*125 a. 12 b. 9 c. 14 d. 7

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(#M40153108) TCS Numerical Ability question Maths Keep an EYE

Find the number of zeroes in the expression 15*32*25*22*40*75*98*112*125
a. 12
b. 9
c. 14
d. 7

Asked In TCS santhana krishnan (8 years ago)

Solved AYAN MONDAL Read Solution (18)

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AYAN MONDAL  (8 years ago) Best Solution

(3*5)*(2*2*2*2*2)*(5*5)*(2*11)*(2*2*2*2*5)*(5*5*3)*(2*7*7)*(2*2*2*2*7)*(5*5*5)
there are 9 (5*2) pairs which gives zero
so.no of zeros 9

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ajay kulkarni  (8 years ago)

no. of zeros depend upon no. of 5 and 2,i.e 5*2=10,i.e one zero.
there no. of 5 lees than no. of 2. Hence no.of zero equal to the no. of zero present.
for 15=5*3 i.e one 5.
similarly,25=5*5,40=5*8,75=5*5*3,125=5*5*5
total no. of 5 are 9
hence there 9 zeros are present.

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aditi apurva  (8 years ago)

b.9
counting the pairs of 5*2

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keerti tiwari  (8 years ago)

no of zeros=pair of 5*2
no of 5 =9
so 9zeros

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Jhilik Sil Sarma  (8 years ago)

answer is 9

Is this solution Helpfull? Yes (1) | No (1)  

jagannath  (8 years ago)

number of zeros depend on number of 5's & 2's
in above expression number of 2's are more than number of 5's
so total number of 5's is 9
number of zeros==9

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Arunima   (8 years ago)

NUMBER OF FIVE IS 9 SO NUMBER OF 0 WILL BE NINE

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Pallavi Ashok Thakare  (8 years ago)

b.9 counting the number of zeroes

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RAKESH KUMAR YADAV  (8 years ago)

no of 5=9
hence no of zero=9

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satyam  (8 years ago)

9 as max power of 5 is 9

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tushar  (8 years ago)

solution is 9..as it contain 9 pairs of 2*5

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B MEENAKSHI SHESHADRI  (8 years ago)

9 zeros-5^9*2^14 means 9 zeros

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Pushan Sen  (8 years ago)

9
break the expression up, conveniently, 15*32, 25*22, 40*75, (98 or 112)*125
480*550*3000*98*14000
264000*98*42000000
x*10^9

x is a number ending with 24
thus 9

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Ravi bisariya  (8 years ago)

no. of pairs of 5*2= no. of zeroes
here 5*2= 9 pairs thats why 9 pairs ans

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gyan prakash kumar  (8 years ago)

b.9 in finding number of zeros means simply find no. of five because when 5 multiply with even number get zero so we simply count no. of 5

3*5*32*5*5*22*5*8*5*5*3*98*112*5*5*5
so number of5=9

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sai vikas  (8 years ago)

15=3*5
25=5*5
40=8*5
75=5*5*3
125=5*5*5
total no. of 5 's is 9

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anjali  (8 years ago)

no of zeros are formed with how many pairs of 5*2 are there so there are (5*3)*(2*2*2*2*2)*(5*5)*(2*11)*(2*2*2*5)*(5*5*3)*(2*2*7)*(2*2*2*2*7)*(5*5*5)
so there are no of total 5-9
total no of 2-12
so there are 9 pair of 2 and 5 formed

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nidhi  (6 years ago)

m4maths pls provide us right answers.how we get to know which one answer is correct or which one is wrong

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