Latest TCS Aptitude Question SOLUTION: A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21. What is the remainder left, when twice the number is divided by 3D? 13 b) cannot

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A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21.
What is the remainder left, when twice the number is divided by 3D?
13 b) cannot be determined c) 3 d) 42

Asked In TCS divyasree (8 years ago)

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gourav  (8 years ago)

ans is 3, it is because
let number is x,and quotient is A . D is divisor,and R is remainder= 8
then x = A*D + 8 --------------(I)
in second situation let quotient is B , 3D is divisor and R is remainder = 21
then x = B*3D +21 -----------(II)
=>
AD +8 =3BD +21
or AD - 3BD =21 - 8 = 13
or D (A- 3B) =13*1
or D=13 ,and A -3B = 1 , IF B = 1 ,then A = 4
NUMBER X = 4*13 + 8 = 52+8 = 60
If 60*2 is divided by 3D =3*13 =39,
120/39 = 3 is quotient,and REMAINDER = 3

Is this solution Helpfull? Yes (22) | No (3)  

Soham Dey  (8 years ago)

X=aD+8.....(1)
X=b3D+21.....(2)
Multiplying (1) with 3
3X=3aD+24.....(3)
Subtracting 2 from 3...
2X=3D(a-b)+3...
So 2X/3D=(a-b)+3/3D...
So remainder is 3.... :-)

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bidyut ghosh  (8 years ago)

42
3Dk+21=y
2(3Dk+21)=2y
3D(2k)+42=2y
remainder =42

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