Latest R-SAT Aptitude Question SOLUTION: The batting average of a cricketer for 87 innings is 40 runs. his highest score exceeds the lowest score by 238 runs. if these two innings are excluded the average of remaining inn

Total No of runs=87*40=3480
Excluding Highest and Lowest score, total runs=85*38=3230
now 3480-3230=250 because addition of both score lowest and highest.
SO let x is lowest score
x+(x+238)=250
x=6 and highest score=244

[1] Average means equal re-distribution of something like money, bananas, fields etc, among all existing
groups after gathering those things from groups.
eg.
If Mohan, Sohan and John, each wants to equally share their daily's income.Suppose, today they
earn Rs. 52, Rs. 42 and Rs. 56 respectively and they decide to have equal amount of money. They
go to a place and then Mohan collects Rs.42 from Sohan and Rs.56 from John and he includes self
also. He adds the total money that was Rs. 150.

He divides the Total money by number of person...as there was need to divide the total money
3 friends...So finally, he gets 150/3 = 50. After this Mohan gives Rs. 50 to each of his friends and
keep the same amount for himself.

finally, we get,
AVERAGE = (Total of something gathered) / (Total no of divisions)

Like that, AVERAGE run per inning = (Total runs of all innings) / (Total no. of innings)
It gives,
Total runs of all innings = AVERAGE run per inning * Total no. of innings
= 40*87
= 3480

Assume that,
Minimum score of cricketer is x
Then, Maximum score should be 238+x

After excluding this 2 scores, We have the total runs of all 85 innings = 3480- (238+x+x)

According to the question,
Total runs of all 85 innings / 85 = 38
[3480 - (238 + 2x)] / 85 = 38
238 + 2x = 3480 - 3230
x = 12/2
x = 6
So the highest score of the cricket will be 238 + x = 244
and option(b) is correct one.

guru how u got 570 as sum of first and last??

Total no of runs=87*40=3480
Excludng first and last=85*38=2910
Sum of first and last=570
X+(x+238)=570
2x=570-238=332
X=166
Highest number is 404
Ans:none

Total no of runs=87*40=3480
Excludng first and last=85*38=2910
Sum of first and last=570
X+(x+238)=570
2x=570-238=332
X=166
Highest number is 404
Ans:none

option (b) is correct

And b is correct

score in 40 innings =40*87
lowest score x
highest score x+238
excluding these two innings avg 38
that is 87*40-(x+x+238)/45=38 solving we get x =6
highest score is x+238=6+238=244

Let lowest score = x runs
then highest scores = (x +238)runs
totals runs of 87 innings = 87*40= 34800runs
totals runs of 85 innings(excluded 2 inning)= 85*38= 3230runs
total run scored in 2 inning= 3480-3230= 250
.......
higest score= 250run