Latest TCS Aptitude Question SOLUTION: In how many ways can 7 different object be divided among three persons so that either one or two of them do not get any object?

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In how many ways can 7 different object be divided among three persons so that either one or two of them do not get any object?

Asked In TCS Gaurav Pratap Singh (8 years ago)

Solved TOSHI JAISWAL Read Solution (4)

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TOSHI JAISWAL  (8 years ago) Best Solution

Case 1: Two guys don't get anything. All items go to 1 person. Hence, 3 ways.

Case 2: 1 guy doesn't get anything. Division of 7 items among 2 guys. Lets say they are called A & B.

a) A gets 6. B gets 1. 7 ways.
b) A gets 5. B gets 2. 21 ways.
c) A gets 4. B gets 3. 35 ways.
d) A gets 3. B gets 4. 35 ways.
e) A gets 2. B gets 5. 21 ways.
f) A gets 1. B gets 6. 7 ways.
Total = 126 ways to divide 7 items between A & B.
Total number of ways for case 2 = 126*3 = 378 (Either A, or B, or C don't get anything).

Answer = Case 1 + Case 2 = 3 + 378 = 381

Is this solution Helpfull? Yes (18) | No (2)  

Gnana Laxmi . V  (8 years ago)

Ans : 381

A B C
7 0 0 3 ways
4 3 0 35*6 = 210 ways
6 1 0 7*6 = 42 ways
5 2 0 21*6 = 126 ways

Total = 3+210+42+126 = 381 ways

Is this solution Helpfull? Yes (7) | No   

Nitesh kumar  (8 years ago)

No of ways distributing objects when 1 person does not get any object is = 3*126 i.e 378 nd
When all the 7 objects will be given to 1 person ..it can be selected in three ways .So 378+ 3 = 381 (ans)

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Saunak Das  (8 years ago)

7c3-(7c1+7c2)= 35-(7+21)=7. Plz check if it would be right or not.

Is this solution Helpfull? Yes (1) | No (7)  

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