Latest Infosys Aptitude Question SOLUTION: if (HE)^H=SHE,where the alphabets takes the values from (0-9) & all the alphabets are single digit then find the value of (S+H+E) a)10 b)13 c)5 d)19 e)data in sufficient

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(#M40154003) INFOSYS Logical Reasoning question quant Keep an EYE

if (HE)^H=SHE,where the alphabets takes the values from (0-9) & all the alphabets are single digit then find the value of (S+H+E)
a)10
b)13
c)5
d)19
e)data in sufficient

Asked In Infosys naveen (8 years ago)

Unsolved Read Solution (17)

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Read Solution (17) :

Divya  (8 years ago)

25^2=625
6+2+5=13

Is this solution Helpfull? Yes (26) | No (1)  

Abhineet kumar  (8 years ago)

(HE)^H must be in the range 21 to 29 so that result must be less then 999 (3 digit ,as SHE) .so as per rule sol
is (25)^2=625. so S+H+E=6+2+5=13 ANS

Is this solution Helpfull? Yes (5) | No (3)  

jaya simha  (8 years ago)

Option (d) mysolution: arrange A-J(0-9) likewise K-L(0-9) and U-Z(0-5)
the code is S=8,H=7,E=4 so 8+7+4=19
if it is wrong correct me guys...

Is this solution Helpfull? Yes (4) | No (14)  

Arifa  (8 years ago)

25^2=625
Here, (HE)^H=SHE
Let H=2
E=5
S=6
So, S+H+E=6+2+5=13
ANS OPTION b)13

Is this solution Helpfull? Yes (2) | No   

priya kumari  (8 years ago)

H-2, E -5 ,S -6
(25)^2= 625

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priya kumari  (8 years ago)

Therefore S+H+E= 6+2+5=13

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naveen  (8 years ago)

(25)^2=625
S+H+E=6+2+5=13
option bis correct answer

Is this solution Helpfull? Yes (1) | No (1)  

AISHWARYA  (8 years ago)

the values that satisfy the given eqn is (25)^2=625
hence s=6
h=2 and e=5
therefore s+h+e=6+2+5=13

Is this solution Helpfull? Yes (1) | No (1)  

riya  (8 years ago)

how the value of h is 2?? can anyone tell ?? because value of alphabets is from range 0-9 !!

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srilatha  (8 years ago)

19 ,where s=8,H=7,E=4

Is this solution Helpfull? Yes (1) | No (3)  

Madhusmita  (8 years ago)

H->2,E->5 25^2=625(SHE) so S=6 S+H+E=13

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sandhya velamala  (8 years ago)

how the value of h is 2??

Is this solution Helpfull? Yes | No (2)  

Minal Verma  (6 years ago)

as alphabets can have values from 0-9
let S be 0
H be 1
E be 4
14^1=014
0+1+4=5
5

Is this solution Helpfull? Yes | No (3)  

vaibhav  (5 years ago)

here when ever you take two digit power then answer must be a three digit on for suppose

if you take h=1 and e =0 then (10)^1=10 so it is wrong then

you take h=2 then (2E)^2 = S 2 E , SO NOW E MUST NE SAME IN BOTH CONDITIONS SO SUPPOSE TAKE E=1 OR 5 OR 6 THEN ANSWER WILL BE (21)^2=441 SO HERE DOES NOT MATCHES
NOW TAKE E=5 THEN (25)^2 =625 IT WILL SATISFY H AND E

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manmohan rathour  (5 years ago)

(25)^2=625

SHE=625

S+H+E=6+2+5=13

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baby  (5 years ago)

13
25^2=625

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Om Asati  (3 years ago)

(25)^2 = 625 then 6+2+5 = 13

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