Latest TCS Aptitude Question SOLUTION: What will be the remainder of 10102103104105.........150 when divided by 9 ?

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What will be the remainder of 10102103104105.........150 when divided by 9 ?

Asked In TCS Sanjoy (8 years ago)

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Sanjoy  (8 years ago)

using formula of AP ,
Sum = n/2 (a+l) [here n=number of element , a=1st term,l=last term ]
= 50/2 * (101+150)
=6275

6275 mod 9 = 2

Is this solution Helpfull? Yes (14) | No (4)  

Richa  (8 years ago)

Here simple way for division by 9 we need sum,of all dgts thus it is required to count values
In hundred place 1 will be 50 times so 50
0 in tens place 10 time 0*10=0
Looking for 1 to 9 in unit place (100-109,110-119,120-129,130-139,140-149)sum of all values from 1-9 nd 1-9 vlues are repeating 5 time so
=45*5=225
Again,looking for 1,2,3,4, 5 in tens place 110-119,120-129,130-139,150-149,150 1*10+2*10+3*10+4*10+5*1 Now,adding all values
225+50+105 =380
Now 380/9=2 remainder

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Sanjoy  (8 years ago)

sry for d typing mistake
What will be the remainder of 101102103104105.........150 when divided by 9 ?

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pk  (8 years ago)

Is it 101+102+103......+150/9 ??

If it is not so then how can you use AP formula for this??

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Atthuru divya  (8 years ago)

the remainder is 3

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Sanjoy  (8 years ago)

Its almost like an ap series, you can check by any value.

@Rich , You are right . I also thought about that.

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taniya mukherjee  (8 years ago)

the nos are arranged as 10102103104.......150. According to the AP series we can start from 102 not 101 as the series is 10102 , we can consider it as 1 in the 100's place *50 = 50.
next,0 in the 10th place is 8 times and den 1 is for 10 times =10. Therefore 10+(2*10)+(3*10)+(4*10)+(5*10)=150 again when we consider the unit's place we get (0+1 2+3+4+5+6+7+8+9)=45. As it repeats from 102 to 150 i.e for five times i.e 45*5=225-1= 224, as the series is from 102 and not 100.
Now adding all 50+150+224=424
now 424%9= 1. I might be wrong but logically i think this should be the ans.

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puppy  (8 years ago)

6. If 3

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