Latest TCS Aptitude Question SOLUTION: a student rolls two 6 sided red die and one 6 sided blue die what is the probability that number shown on the blue die exceeds both the number on the red die a)1/6 b)5/36 c)55/

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a student rolls two 6 sided red die and one 6 sided blue die what is the probability that number shown on the blue die exceeds both the number on the red die a)1/6 b)5/36 c)55/216 d)1/2

Asked In TCS anindita (8 years ago)

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Biswadeep Sen  (8 years ago)

Let the blue die rolls to 6, so the combinations available are
6>(1,1)
>(1,2)
>(1,3)
.
.
.
>(5,5)
So a total of 5*5=25 combinations,
similar case if the blue die rolls to 5 we will have 4*4=16 combinations, similar for all the other blue dice cases...hence the total is 5*5+4*4+3*3+2*2+1=55
thus the probability 55/216
Thus the t

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Richa  (8 years ago)

Someone please xplntn the method clearly....

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Yashika  (8 years ago)

solution is : 55/216

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devendra kumar  (8 years ago)

C) 55/216

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Sabyasachi Behera  (8 years ago)

B 5/36
2dies are rolled so total no of outcomes 36
The no can't be 7 in a single die . coz 6 face .
So it can be 2,3,4,5,6, total 5no
So it ts 5 /36

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Sonu kumar  (8 years ago)

blue die must be 3,4,5,6 cases (2 can't be possible because 2 red die atleast 1 and 1 means sum =2 and in given question blue die must be greater than sum of two red dies number ok)

1. sum 3==(1,1)=1
2.sum 4=(1,1),(1,2),(2,1)=3
3.sum 5=(1,1),(1,2),(2,1),(2,2),(3,1),(1,3)=6
4.sum 6=(1,1),(1,2),(2,1),(2,2),(3,1),(1,3),(1,4),(4,1),(5,1),(1,5)=10

p(blue

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