Latest TCS Aptitude Question SOLUTION: 100 students appeared for two different examinations 60 passed the first,50 the second and 30 both the examinations.Find the probability that a student selected at random failed in

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(#M40154821) TCS Numerical Ability question Keep an EYE

100 students appeared for two different examinations 60 passed the first,50 the second and 30 both the examinations.Find the probability that a student selected at random failed in both the examination
a)5/6 b)1/5 c)1/7 d)5/7

Asked In TCS Rik (8 years ago)

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keerthana chennamsetty  (8 years ago)

60+50-30=80
100-80=20
20/100=1/5.
so B is the answer.

Is this solution Helpfull? Yes (27) | No (1)  

papolu  (8 years ago)

100 students
60 pass(1)&50 pass(2)
30 pass (both 1&2)
p(aub)=60+50-30=80
probability of selecting a passed student =80/100
not selecting=(1-80/100)=20/100=1/5

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svs.pradeep  (8 years ago)

b ,in first round the probability of failures is 40/100 in second round it is 50/100. the product of these two gives 1/5 as answer

Is this solution Helpfull? Yes (5) | No (1)  

arundhati ubhad  (8 years ago)

n(1)=60[no.of students passed in first exam]
n(2)=50[no.of students passed in second exam]
n(1∩2)=30[no.of students passed in both exams]
[n(AUB)=n(A)+n(B)-n(A∩B)]
no. of students passed = (60+50)-30
=80
no. of students failed in both exams = 100 - 80
=20
PROBABILITY = 20/100
=1/5

Is this solution Helpfull? Yes (5) | No   

S Gokulraj  (6 years ago)

first subject 60 pass and 40 fail
second subject 50 pass and 50 fail
bot pass 30
first only pass 60-30=30
second only pass 50-30=20
total pass 30+30+20=80
both fail=100-80=20
so 20/100=1/5

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Richa  (8 years ago)

We are needed to find (A' intersection B')= (1-60/100)(1-50/100)
1/5 ans

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Mohammad Mursaleen  (8 years ago)

Answ is 1/5

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prabin  (8 years ago)

20c1/110c1=1/5

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prabin  (8 years ago)

20c1/100c1=1/5

Is this solution Helpfull? Yes (1) | No (1)  

Manisha gouri  (7 years ago)

total students are 100
30 pased first 20 passed second 30 passed both by venn diagram
30+30+20=80
100-80=20
20/100=1/5
so, ans is 5

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gowtham  (4 years ago)

60+50-30=80
100-80=20
20/100=1/5
ans: (b) 1/5

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iti  (2 years ago)

p(aub)=p(a)+a(b)-p(a-b)
p(aub)=0.6+0.5-0.3
p(aub)=0.8
p(aub)'=1-p(aub)
p(aub)'=1-0.8
p(aub)'=0.2

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