Latest TCS Aptitude Question SOLUTION: .Rs19266 is distributed among a b c such that a gets 4/45 of what b and c get together and c gets 7/12 of what a and b gets together. Find c share a)7098 b)60

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.Rs19266 is distributed among a b c such that a gets 4/45 of what b and c get together and c gets 7/12 of what a and b gets together. Find c share a)7098 b)6084 c)4056 d)8112

Asked In TCS dhritiman (8 years ago)

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Read Solution (8) :

Vidyakant soni   (8 years ago)

Let A's share is x and similarly for b & c, y& z
According to question
19266=x+y+z
& z=7/12 of (x+y)
So x+y = 12/7 of z
Putting value of x+y in 1st equation
19266=z+z(12/7)
On solving z=7098

Is this solution Helpfull? Yes (16) | No   

Sambit Paul  (8 years ago)

a+b+c = 19266
49(b+c)/45 = 19266
19(a+b)/12 = 19266
Hence:
a + 19266*(45/49) = 19266 = 1572.73
b = 19266*12/19 - a = 10595.27

Therefore:
c = 19266*45/49-b = 7098

Is this solution Helpfull? Yes (2) | No (1)  

Jinal  (8 years ago)

a = 4/45(b+c)
c= 7/12(a+b)
a+b+c = 19266 -----eq1
Now,replace value of a+b by using c after multipy by 7/12 both side
7/12c +c = 19266*7/12

c = 19266*7/19
ans is 7098

Is this solution Helpfull? Yes (2) | No   

Amit Bansal  (8 years ago)

a+b+c=19266
&
12c=7(b+c)
12c=7*(19266-c)
19c=134862
c=7098

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Anjali kumari  (8 years ago)

ans a)7098

Is this solution Helpfull? Yes (1) | No   

Amitabh Sinha  (8 years ago)

c = (7/12)(a+b)
a+b=12c/7
a+b+c=19266
12c/7 + c = 19266
on solving we get c= 7098
thanks.

Is this solution Helpfull? Yes (1) | No   

Rajini Kumar AV  (8 years ago)

Let a+b+c=19266
a=4/45 of (b+c) ----- (1st equation)
c=7/12 of (a+b) ----- (2nd equation)

From 2nd Equation,
c=7/12 of (a+b)
(a+b)= 12/7 of c ----- (3rd equation)

Sub 3rd Equation in,
a+b+c=19266
12/7 c + c = 19266
12c+7c = 19266 * 7
19c=134862

c=7098 (Answer)

Is this solution Helpfull? Yes (1) | No   

NIKHIL JAIN  (8 years ago)

a=4/45(b+c) ........1
c=7/12(a+b)

or, (a+b)=12/7c..........2

Also a+b+c=19266
From 2, 12/7c+c=19266
c=19266*7/19=7098

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