Latest TCS Aptitude Question SOLUTION: consider sequence 1 ,-2, 3, -4,5,-6....., what is average of first 200 numbers

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consider sequence 1 ,-2, 3, -4,5,-6....., what is average of first 200 numbers

Asked In TCS mounika undi (8 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Naveen  (8 years ago)

Two series:
1st series: 1,3,5,7......199 Sum = [n(a+l)]/2 = 10000
2nd series: -2,-4,-6....-200 Sum = [n(a+l)]/2 = -10100
Average = [10000-10100]/200 = -[1/2] = -0.5

Is this solution Helpfull? Yes (14) | No (1)  

mounika  (8 years ago)

(1-2)+(3-4)+(5-6)+......(199-200) = -1(100)
average = -100/200 = -0,5

Is this solution Helpfull? Yes (5) | No   

harshit singh  (8 years ago)

sum of 1st two number 1-2=-1
3&4th number 3-4=-4
there will ne 100 pairs like this
total sum =-100
average -0.5

Is this solution Helpfull? Yes (2) | No   

sonu sinha  (8 years ago)

we can write as follows..
(1 , 3 , 5 , 7.............199) + (-2 , -4 , -6 , - 8 ......... -200)
(1+199)/2 +(-2 -200)/2
200/2 +-202/2
(100-101)/2
=0.5

Is this solution Helpfull? Yes (2) | No   

devi vara prasad mudili  (8 years ago)

-0.5 because is there are 100 p+ve and 100 n-ve no's so average of these are -100/200

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saikiran  (8 years ago)

18. On the calenders page shown a 3*3 block of numbers has a sum of 198. What is the smallest number in the block in april month
sunday
mon
Tuesday
Wednesday
Thursday
friday
Saturday


1
2
3
4
5



30



a)14 b)10 c)9 d)13
19.we know that the vertices of quadrilateral A,B,C,D are 2,5,6,3 cms respectively from a point p what is the largest possible area in sq.cms of ABCD a)16 b)48 c)32 d)24
20. Rs.7791 is divided among shills=a ,beena and chris in such a way that if Rs.34 Rs.32 and Rs.29 be deduced from their respective shares they are left with money in the ratio 8:6:12 find shilas share in rupees a)2402 b)1798 c)1808 d)2397

Is this solution Helpfull? Yes | No   

Mal reddy  (8 years ago)

Given sequence containing odd numbers and -ve even numbers,
so that ,sum of even numbers =200/2(2*(-2)+(200-1)*-2)
=-40200
sum of odd numbers=200/2(2*(1)+(200-1)*2)
=40000
total sum=40000-40200
=-200
Average=total/200
=-200/200
=-1.

Is this solution Helpfull? Yes | No (1)  

Sachin  (8 years ago)

Ans = -0.5
bcz (100-101)/2

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