Latest TCS Aptitude Question SOLUTION: a spider web consists of 3 concurrent lines forming radial support for 20 concentric regular hexagon .the hexagon vertices are 5mm from their immidiate neighbour. if the innermost

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(#M40154967) TCS Numerical Ability question Keep an EYE

a spider web consists of 3 concurrent lines forming radial support for 20 concentric regular hexagon .the hexagon vertices are 5mm from their immidiate neighbour. if the innermost hexagon has a side length 3mm how many meters is the length of the entire web including the 3 diagonals ?

Asked In TCS amit kumar (8 years ago)

Solved Piyush Chaturvedi Read Solution (8)

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Piyush Chaturvedi  (8 years ago) Best Solution

the correct answer is 6.648 meters
6060 is correct from the below solution but the sum length of diagonals is 6*98=588
so 6.060+0.588=6.648 meters

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Angad  (8 years ago)

for perimeter of all hexagon =6*(3+8+13+...........20th term.)
sum will be 6060 mm
and for length of one diagonal find 20th term=98

so total length =6060+294=6354 mm=6.354 m
if i made any mistake pl correct me ......

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shubham gupta  (8 years ago)

20*(3+98)/2 =1010
1010*6= 6060 (hexa =6)
series last is 98 so bcz 6line from the center of hexa.
98*6 =588

so entire web length = sum of perimeter of all hexa + the length from centre to last hexa
= 6060 + 588
= 6648 ( 6.648 meter)

6.648 meter is ri8

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tany  (8 years ago)

side of innermost hexagon = 3mm
side of next hexagon = 8mm
it goes on as series 3,8,13... 20th terms
total length of smallest hexagon = 6 * 3= 18mm
next hexagon length = 6 * 8= 48mm

sum of all hexagon sides = 20/2 * (2*18 + 19 * 30) = 6060mm
sum of length 3 diagonal = 3*(sum of the series (3,8,13,...98)
3 * 1010 = 3030

Total length of the spider web = 6060 + 3030 = 9090mm

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Santosh Paik  (8 years ago)

wats the correct answer

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Santosh Paik  (8 years ago)

either 7.5 or 6.04

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Angad  (8 years ago)

@piyush in question it is saying only three diagonals but added extra three why?

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Leela  (2 years ago)

6.060+0.285=6.285 meters
because 3 diagonals only...And the diagonals are starting from the vertices of first hexagon i.e. the
inner most one.

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