Latest Capgemini Aptitude Question SOLUTION: Two trains whose respective lengths are 240 m and 360 m cross each other in 30 seconds when they are moving in opposite directions and in 1 minute 40 seconds when they are moving i

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Two trains whose respective lengths are 240 m and 360 m cross each other in 30 seconds when they are moving in opposite directions and in 1 minute 40 seconds when they are moving in the same direction. What is the speed of the faster train (kmph)
a. 39.2 b. 36.6 c. 46.8 d. 33.33 e. 49.2

Asked In Capgemini harika sharma (8 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

Mithilesh Times  (8 years ago)

Given that L1=240 and L2=360
so we know that t=s/v, then 30=240+360/v1+v2, =>v1+v2=20.......(1)
and v1-v2=600/100=6.....(2)
after solving the both equations we get
v1=13 and v2=7
Now we have to convert 13*18/5=46.8
(c.) 46.8 is correct answer.

Is this solution Helpfull? Yes (26) | No (1)  

Bhargavi  (8 years ago)

240+360/x+y=30 here x &y are speeds of 2 trains 600/30=x+y I.e x+y =20 we add their speeds bcoz dey r moving in opposite direction similarly 600/x-y=100sec by solving we get x & y values and speed of faster train is 46.8

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chandrasekharkonchada  (8 years ago)

46.8 will be the ans as s=d/t here s1+s2=240+360/30, s1-s2=6 and
s1=7,s2=13,we get faster train speed as 13*18/5=46.8

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gvkrishna  (6 years ago)

let s1, s2 be the speed of the two trains
opposite direction 30=240+360/s1+s2
gives s1+s2 = 20
same direction 100=240+360/s1-s2
gives s1-s2=6
solving two equations
s1=13m and s2=7m
13*18/5 = 46.8kmph

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bikram kumar  (7 years ago)

S1+S2=20
S1-S2=6
S1=13
S2=7
S1=(13*18)/5=46.8kmph

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Vikash kumar  (7 years ago)

given that L1=240 and L2=360
consider the speed of first train is x and the speed of another train is y
accourding to concept of average speed
avrage time=total distace / tota speeed
30=600/x+y(when the train is in opposite direction)...(1)
100=600/x-y(when the train is in same direction )...(2)
now solv equation 1 and 2 and enjoy the answer...

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