Latest Elitmus Aptitude Question SOLUTION: is (a*b*c) is even? 1. a-b=b-c 2. a-c=16 Guys plz solve this. I had given today. plz tell correct ans.

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(#M40155176) ELITMUS Logical Reasoning question Data sufficiency Keep an EYE

is (a*b*c) is even?

1. a-b=b-c
2. a-c=16
Guys plz solve this. I had given today. plz tell correct ans.

Asked In Elitmus nikita (8 years ago)

Unsolved Read Solution (30)

Is this Puzzle helpful?   (18)   (9) Submit Your Solution Cryptography

Read Solution (30) :

Yamini Kant Mahato  (8 years ago)

Neither stat1 nor Stat2 gives the solution alone.And Both statements also can't

Is this solution Helpfull? Yes (30) | No (1)  

Rahul Pandey  (8 years ago)

both 1 & 2 are not sufficient to answer the question.
case 1 : b is arithmetic mean of a & c ; if a = 15 , c = 7 , then b = 11 , hence abc is odd ; but a = 8 , c = 4 gives b = 6 and abc is even, hence 1 alone cannot determine
case 2 : a-c = 16, its obvious nothing can be determined about abc from this statement alone.
Now, combining both statements , say, a = 25 , b = 17 , c = 9 , (a - c = 16 and a-b = b-c) then abc is odd , but, if a = 24 , b = 16 and c = 8 (a - c = 16 and a-b = b-c) gives abc even.
hence, nothing can be said about the product abc from the two statements

Is this solution Helpfull? Yes (17) | No   

swati  (8 years ago)

a=24
b=16
c=8

then,
a-b=b-c
is
26-16=16-8
8=8
and
a-c=16
is
24-8=16
and then (a*b*c) is 3072 which is a even no.

Is this solution Helpfull? Yes (7) | No (14)  

Yamini Kant Mahato  (8 years ago)

Crypto Was:
X D L
H A E
-----------
D E P H
3 P K P
__ A D __
------------
P __ __ K D H I AM UNABLE TO FLASH BACK THE EXACT 2 CHARACTERS SO I LEFT BLANK.BUT I AM GIVING THE EXACT SOLUTION OF THE ABOVE CRYPTO:

5 4 7
3 6 9
________
4 9 2 3
3 2 8 2
1 6 4 1
___________
2 0 1 8 4 3 SO SIMPLY YOU HAVE TO PUT THE VALUE OF 1 AND 0.I CAN'T CALL BACK THE VALUE OF 0
AND 1.
Q.1 WAS:D*H*E=4*3*9=108
Q.2 WAS:P*D*K=2*4*8= 64
Q.3 WAS:X*P*__=5*2*1= 10 THE VALUE OF 1 CAN'T CALL FRIENDS.

Is this solution Helpfull? Yes (5) | No (6)  

as  (8 years ago)

both alone can give the ans

Is this solution Helpfull? Yes (3) | No (6)  

ramen maji  (8 years ago)

it a=3 b=2 c=1 then (a*b*c)=6 is even no and a,b,c are distinct values as per stmt 1 a-b=1 & b-c=1 so a-b=b-c which gives the solution alone.

Is this solution Helpfull? Yes (2) | No (4)  

Yamini Kant Mahato  (8 years ago)

Hii...REENA..Almost company hiring through overall marks cutoff.It depends on Company to company... Like Accenture hiring through overall score..It may be negative marking in any section..But finally you have score overall more than 100 marks as well as you have to also come under selected college list...And in word of CGI...This company will call if you have more than 50 Marks...!!!

Is this solution Helpfull? Yes (2) | No (1)  

Akansha  (8 years ago)

form statement 2 the diff of a and c is even(i.e., 16)
as odd-odd=even and even-even=odd so both a and b are either two even numbers of odd numbers.

From statement 1 it is clear that a b and c are three consecutive numbers.
for example a=44,b=45,c=46 so a-b=44-45=-1, b-c=45-46=-1
-1=-1
In three consecutive numbers if two terminal numbers(i.e., a and c in abc) are odd then the middle one is always even and if the two terminal numbers are even then the middle number is always odd

Case 1.
let us assume that if both a and b (statement 2) are even then b is odd(by statement 1)
then a*c=even*even=even
(a*c)*b=even*odd=even

Case 2.
let us assume that if both a and b (statement 2) are odd then b is even(by statement 1)
then a*c=odd*odd=odd
(a*c)*b=odd*even=even

In Both the cases the result is even so YES a*b*c is even.
And for calculating the answer both statements are required.

Is this solution Helpfull? Yes (2) | No (3)  

Reena  (8 years ago)

in elitmus i got
66% in verbal
87% in problem sloving
30% in quant ????is there any chance to get the call?????

Is this solution Helpfull? Yes (1) | No (14)  

Ishani Rajpal  (8 years ago)

Solving statement 1 & 2 : a+c=2b and a-c=16, we get 2a-2b=16 ie. a-b=8. Now solving a-b=8 and a-c=16, we get b-c=8. Now we have 3 eqns a-b=8, b-c=8, a-c=16. Putting values a=20, b=12, c=4, we get abc as even but putting values a=16, b=8, c=0 we get abc=0 which is neither even nor odd. So neither statement 1 nor 2 gives the solution.

Is this solution Helpfull? Yes (1) | No   

Ramen Guchhait  (8 years ago)

stmt1: a+c=2b so 2b is a even number and it's getting by addition of a+c
now it is possible when odd+odd=even and even+even=even so from the statement 1 it can't say that a,c is actualy even or odd and b is even or odd

stm2:a-c=16 again 16 is even number and its getting by the rule odd-odd=even or even - even=even so we can say that a,c is even or odd so statement 2 is not sufficient

Both stm1&stmt2: from both the statement we can't say a,b,c is even or odd so

answer is both statement 1 and statement 2 is not sufficient to give the answer need another data

Is this solution Helpfull? Yes (1) | No   

ashwini  (8 years ago)

1 is sufficient since they form AP
2 cannot prove us whether product can be even or not

Is this solution Helpfull? Yes (1) | No   

Ravi Kumar Soni  (8 years ago)

cases
1. odd * odd * odd = odd
2. odd * odd * even = even
3. odd * even * even = even
4. even * even * even = even

so... its only first case that we have to work on... to confirm about the question
NOTE : so here we need to prove ...that case 1st wont exist here.
if case 1 doesn't exist ....yes we can say ..it is even
but if case 1 exist then we can say... some are even some are odd... so no conclusion.

now choose statement 2
put simple odd values a= 17 and c=1
17-1 = 16 true
also put this in 1 eq.
17-b = b -1
this will yield b = 9
so...a=17 , b =9, c = 1
this holds true for both statements
but when we check
17*9*1 = odd

so there exists case 1..
so no conclusion

Is this solution Helpfull? Yes (1) | No   

Raj Kishore Mahato  (7 years ago)

Even using hit and trail method you will get a=24 b=16 & c= 8

Is this solution Helpfull? Yes (1) | No   

MUKUL BAGRE  (7 years ago)

Both together are sufficient.

Is this solution Helpfull? Yes (1) | No   

priyanka  (8 years ago)

1. Perimeter of rhombus is equal to perimeter of circle. Longest distance between two points in rhombus is 80. Area of rhombus is 2400 cm^2. Find area of circle.
Options: 10000, 62500, 2500, one more I don't Remember.

Someon Please post this que. I am not able to post.

Is this solution Helpfull? Yes | No   

Reena  (8 years ago)

in elitmus i got
66% in verbal
87% in problem sloving
30% in quant ????is there any chance to get the call?????

Is this solution Helpfull? Yes | No (9)  

Vikas Jha  (8 years ago)

Anybody remember the horse problem in lr di section please post it.. !!

Is this solution Helpfull? Yes | No (1)  

atul kumar singh  (8 years ago)

a=18
b=10
c=2
a*b*c=even no
18-10=8-2
18-2=16

Is this solution Helpfull? Yes | No (2)  

vikash ranjan  (8 years ago)

both are not true
1) Let a=3 b=2 c=9
2- 3 != 3 -9
2)
3-9 != 16

Is this solution Helpfull? Yes | No   

Avinash Singh  (8 years ago)

In cryptarithmetic questions ...are options also given?

Is this solution Helpfull? Yes | No   

Akansha  (8 years ago)

There is a minor mistake in line no 2 of my answer i've posted above.

The correct/updated answer is:

from statement 2 the diff of a and c is even(i.e., 16)
as odd-odd=even
even-even=even
odd-even=odd
even-odd=odd
so it is clear that both a and b are either two even numbers of odd numbers.

From statement 1 it is clear that a b and c are three consecutive numbers.
for example a=44,b=45,c=46 so a-b=44-45=-1, b-c=45-46=-1
-1=-1
In three consecutive numbers if two terminal numbers(i.e., a and c in abc) are odd then the middle one is always even and if the two terminal numbers are even then the middle number is always odd

Case 1.
let us assume that if both a and b (statement 2) are even then b is odd(by statement 1)
then a*c=even*even=even
(a*c)*b=even*odd=even

Case 2.
let us assume that if both a and b (statement 2) are odd then b is even(by statement 1)
then a*c=odd*odd=odd
(a*c)*b=odd*even=even

In Both the cases the result is even so YES a*b*c is even.
And for calculating the answer both statements are required.

Is this solution Helpfull? Yes | No (4)  

AMAN KUMAR JHA  (8 years ago)

NO,
make it two equation
a+c=-2b and a-c=16 NOW solve it ..
we ll have another equation a=b+8 ,which clears that a is 8 more then the b .
now substitute value of b=1 we will get a=9 abd c=-7
a*b*c=-63 (ODD).

Is this solution Helpfull? Yes | No   

sumanta karak  (7 years ago)

it is consecutive even and odd.

Is this solution Helpfull? Yes | No   

BHARAT KUMAR  (7 years ago)

both statement are not sufficient to hive answer (if a=19,b=11,c=3, )

Is this solution Helpfull? Yes | No   

thirumala  (7 years ago)

a=20
b=12
c=4
1. 20-12=12-4
2. 20-4=16

Is this solution Helpfull? Yes | No   

RAJEEV  (7 years ago)

a= 18
c=2
a-c= 18-2= 16

a-b = b-c (let b= x)
18-x = x-2
2x= 20
x= 10
So, b= 10
Put all the value in a*b*c = 18*10*2 = 360
So this is even

Is this solution Helpfull? Yes | No (2)  

gmswacc  (7 years ago)

Please tell the confirmed, verified and correct Answer, please comment on this fast

Is this solution Helpfull? Yes | No   

Md. Irshad Alam  (7 years ago)

a-b=b-c
a-c=2b
16=2b
b=8
one number is even i.e. b=8
product of a*b*c=even, if any of one number of them is even
i.e. a*8*c=even .

Is this solution Helpfull? Yes | No (2)  

Digesh Singh Bisht  (1 year ago)

Both 1 & 2 are not sufficient to answer the question.

Let a = 20 b=4 c =12 then both the equation will be satisfied
but
if we take a =19 b= 11 c=3 then also both the equation will be satisfied .
and much more pairs can be made so we cannot give a unique solution .

Is this solution Helpfull? Yes | No   

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