Latest tcs Aptitude Question SOLUTION: . Hari has a piece of cake 60 cm long. He gives Raja half of it. He then gives Gopal 1/4th of what is left. After giving a piece to Sahi, be is left with 1/10th of the original. Ho

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. Hari has a piece of cake 60 cm long. He gives Raja half of it. He then gives Gopal 1/4th of what is left. After giving a piece to Sahi, be is left with 1/10th of the original. How much did he give to Sahil ? A.21.5 cm B.16.5 cm C.Rs. 5 D.Rs. 3

Asked In tcs Sowntharya.K (8 years ago)

Unsolved Read Solution (17)

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Read Solution (17) :

shalini kumari singh  (8 years ago)

Total amount=60 cm long .
He gives Raja 1/2 of it i.e=1/2*60=30 cm long.
left with Hari now=60-30=30
Again he gives Gopal 1/4th of what is left i.e=1/4*30=7.5
NOw left=30-7.5=22.5
Now let he gave Sahil=x,
Then A2q, 22.5-x=1/10*60
After solving this we get x=16.5 cm which is required.
So option B will be correct.

Is this solution Helpfull? Yes (27) | No   

sudhansu das  (8 years ago)

LET SAHI TAKE X.
30+7.5+X+6=60
X=16.5

Is this solution Helpfull? Yes (4) | No (2)  

shivam tiwari  (8 years ago)

b 16.5 cm

Is this solution Helpfull? Yes (2) | No (2)  

Sanket Dan  (8 years ago)

Total amount=60cm
then after giving to raja he has left =30cm
then he gives Gopal 1/4of 30cm=7.5cm
left=30-7.5=22.5cm
now let he gives to sahil x cm..
so equation is---->
22.5-x=60*1/6
x=16.5

Is this solution Helpfull? Yes (2) | No (1)  

garima  (8 years ago)

let hari has 60.by giving half(30) to raja,he has 30.by giving 30/4 to gopal,hari is left with(30-30/4)=90/4.90/4-x=60/10, where x is of sahil, x=33/2=16.5

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Shanmuga priya  (8 years ago)

after giving to raja he has 30cm of cake and 1/4 th of 30 is 7.5 is given to gopal then remaing left for hari should be 6 so 30-7.5=22.5 and 22.5-6=16.5 so 16.5cm is given to sahil

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Chandan Bhagat  (8 years ago)

16.5
1/2+1/8+1/8+X=1 ==>x=11/40==>16.5cm

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Antara DE  (8 years ago)

Total amount=60 cm long .
He gives Raja 1/2 of it i.e=1/2*60=30 cm long.
left with Hari now=60-30=30
Again he gives Gopal 1/4th of what is left i.e=1/4*30=7.5
NOw left=30-7.5=22.5
After giving a piece to Sahi, be is left with 1/10th of the original
so 60*(1/10)=6
since, 22.5-6=16.5
ans

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Sunny Grover  (8 years ago)

answer is 16.5

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ganesh chode  (8 years ago)

16.5 cm (b)

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sukanya  (8 years ago)

answer is 16.5

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Manasa  (8 years ago)

Half of 60 is 30
1/4th of 30=7.5
30-7.5=22.5 is left
10% of 60=6
22.5-6=16.5

Is this solution Helpfull? Yes | No (1)  

komal kumari  (8 years ago)

H=60 cm
he gives raja half of 60 cm i.e=30 cm
and left ammount is 30 cm
again he gives 1/4 part to gopal i.e=7.5
and remaining part =22.5
and condition is remaining part - sahi's part=1/10 of original
ie.=> 22.5-x=1/10(60)
=22.5-6=x
=>x=16.5cm
so sahi get 16.5cm

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srimanth  (8 years ago)

16.5 answer

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Sethuraman  (8 years ago)

Hari initially have 60 cm
he gives raja 30cm
For gopal 7.5cm
for Sahi X
finally he return with 6cm
30+7.5+6+x=60
X=16.5

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Fairlin Jenefa  (8 years ago)

b16.5 cm
Total amount=60 cm long .
He gives Raja 1/2 of it i.e=1/2*60=30 cm long.
left with Hari now=60-30=30
Again he gives Gopal 1/4th of what is left i.e=1/4*30=7.5
NOw left=30-7.5=22.5
Now let he gave Sahil=x,
Then A2q, 22.5-x=1/10*60
After solving this we get x=16.5 cm which is required.
So option B will be correct.

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navi chinnu  (7 years ago)

16.5 is the ans

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