Latest TCS Aptitude Question SOLUTION: Find the number of zeros in the expression 15*32*25*22*40*75*98*112*125 7 12 9 14

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(#M40155595) TCS Numerical Ability question Keep an EYE

Find the number of zeros in the expression 15*32*25*22*40*75*98*112*125

7
12
9
14

Asked In TCS JAY GAJJAR (8 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

niki goyal  (8 years ago)

answer is 9
15-3*5
32-2*2*2*2*2
25-5*5
22-2*11
40-2*2*2*5
75-5*5*3
98-2*7*7
112-2*2*2*2*7
125-5*5*5
here we will get 0 when 2 is multiplied by 5
and total no. of 2's are-14 and 5's are- 9
so no. of zeroes is according to 5 as it is minimum so ans is 9

Is this solution Helpfull? Yes (20) | No   

sneha pawar  (8 years ago)

9...because its factors involve 9 pairs of 5x2

Is this solution Helpfull? Yes (3) | No (3)  

Deepak Suyal  (8 years ago)

after multiply =1086624000000000
count no. of zeroe's which are 9 .
ans -9

Is this solution Helpfull? Yes (3) | No (7)  

Manisha Yadav  (8 years ago)

factor pairs of 5x2 in 15*32*25*22*40*75*98*112*125 is "9".......... so the ans is 9

Is this solution Helpfull? Yes (2) | No   

Jagapathi  (8 years ago)

7
5*2 combimations

Is this solution Helpfull? Yes | No (2)  

Rajalakshmi  (8 years ago)

Calculate number of 5's and number of 2's in each number given in the question that means take LCM of each number which gives you number of 2's and 5's

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harish  (8 years ago)

how long the question is!!!! it doesn't matter. just fing the factors for each number and see the number of combination of 2's and 5's. here
15=5*3
32=2*2*2*2*2
25=5*5
22=2*11
40=2^3*5
75=5^2*3
98=7^2*2
112=2^4*7
125=5^3
here in total there are 9 pairs of 2*5, so the number of 0's are 9.

Is this solution Helpfull? Yes | No (1)  

Sambit S. Mondal  (8 years ago)

No of zero depends upon no of Fives present as no of two is clearly going to be more than no of 5s.
So the answer is 9.. as 15 have 1 no of 5, 25 has 2 no of 5s... and so on

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Ankit  (7 years ago)

x1+x2+x3=13 wher x1,x2,x3>=1 and x1,x2,x3

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bvg sai kumar  (7 years ago)

write every number into its prime factors form at last we will get 5^9 *2^13 *3^4 *11*7^2 .so no of zeroes will be equal to the power of 5 as no of 2's available are more than 5. so answer is 9

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