Latest CTS Aptitude Question SOLUTION: A, B and C can do a piece of work in 20, 30 and 100 days respectively. If A worked alone on the first day, B worked alone on the second day, C worked alone on the third day, A work

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(#M40156273) CTS Numerical Ability question Keep an EYE

A, B and C can do a piece of work in 20, 30 and 100 days respectively. If A worked alone on the first day, B worked alone on the second day, C worked alone on the third day, A worked alone on the fourth day, and so on, then in how many days the work got completed?
1) 29 days
2) 28 days
3) 31 1/2 days
4) Can't be determined

Asked In CTS ABHINAV PUSHPAM (8 years ago)

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Avinash Nishad  (8 years ago)

A's, B's and C's 1 day work = 1/20 + 1/30 + 1/100

Total 3 day's work = 28/300
Total 30 day work = 280/300
Remaining work = 20/300 = 1/15
Now A's 1 day work = 1/20
Then remaining work = (1/60)/(1/30) = 1/2
Now, B's then B complet the remaining work in 1/2
Total number of days = 31 1/2 days.

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kamisetty karthik  (7 years ago)

take lcm of 20,30,100 it is 600. a can complete 30 works in a day,b can complete 20 works in a day, c can complete 6 works in a day,togeather abc can complete 56 works per day..in 30 days abc completes 560 works on so remaining 40 works left on 31 day a complete 30 works remaining we have 10 works c completes in hald day so ans is 31 1/2.

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