Latest CTS Aptitude Question SOLUTION: A, B and C can do a work in 24, 32 and 60 days respectively. They start working together. A left after 6 days B left after 8 days. how many more days are required to complete the

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(#M40156316) CTS Numerical Ability question Keep an EYE

A, B and C can do a work in 24, 32 and 60 days respectively. They start working together. A left after 6 days B left after 8 days. how many more days are required to complete the whole work?
a) 30
b) 25
c) 22
d) 20
e) None of these

Asked In CTS ABHINAV PUSHPAM (8 years ago)

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NARESH CNR  (8 years ago)

(A+B+C)'s 1 Day work = (1/24+1/32+1/60) ;- LCM of 1/24 + 1/32 + 1/60 is (20+15+8)/480
= 43/480
A left after 6 days means = 6*(43/480) = 258/480
B left after 8 days means here 6 days already worked with A so only 2 days extra worked compared to A
i.e.. 2(1/32+1/60) = 2(15+8)/480 = 46/480
remaining work = 1-[(258/480)+(46/480)]
= 1-[304/480]
= 1-[19/30]
= 11/30
C can do 11/30 remaining work
C's 1 Day work = 1/60
11/30 can complete in (11/30)*60 = 22 Days

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raunak kumar jha  (8 years ago)

6day=6*(43/480)=43/80
8day =8*(23/480)=23/60
total 14 day=43/80+23/60=221/240
remaining work=1-221/240=19/240
c will do=19/240-1/60=1/8
so,c will take 8 days
total=8+6+8=22days

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