Latest CTS Aptitude Question SOLUTION: An orange vendor makes a profit of 20% by selling oranges at certain price. If he charges Rs. 1.2 higher per orange he would gain 40%. Find the original price at which he sold an o

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(#M40156317) CTS Numerical Ability question Keep an EYE

An orange vendor makes a profit of 20% by selling oranges at certain price. If he charges Rs. 1.2 higher per orange he would gain 40%. Find the original price at which he sold an orange.
a) RS. 5.6
b) Rs. 7.2
c) Rs. 4.8
d) Rs. 8
e) None of these

Asked In CTS ABHINAV PUSHPAM (8 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

NARESH CNR  (8 years ago)

Let the CP be Rs. x per orange
Profit = 20%
SP = [(100+profit)/100]*cp
SP = (120/100)*x ==> 1.2x
Now :-
SP =x+ Rs.1.2
Profit = 40% ==> (140/100)*x
Therefore, we can say
1.40x = x+1.2 or x = Rs. 3
Hence, Original SP = Rs 1.2x = Rs. 3.60/-

Is this solution Helpfull? Yes (9) | No (10)  

raunak kumar jha  (8 years ago)

sp=(100+profit%/100)cp
7.2

Is this solution Helpfull? Yes (6) | No (6)  

Aditya singh panwar  (7 years ago)

Let the CP be Rs. x/ orange
Profit = 20%
SP = Rs. 1.20x
Now, If case :-
SP =x+ Rs.1.2
Profit = 40%
Therefore, we can say
1.40x = x+1.2 or x = Rs. 3
Hence, Original SP = Rs 1.2x = Rs. 3.60/

Is this solution Helpfull? Yes (6) | No (3)  

alpa sharma  (7 years ago)

20=(sp-x)*100/x
40=(sp+1.2-x)*100/x
on solving this equations
x=6
sp = 20% of x
therefore,
sp=7.2

Is this solution Helpfull? Yes (6) | No (7)  

SNEKA KANAGARAJ  (7 years ago)

s.p/s.p+1.2 = 120/140
s.p/s.p+1.2 =12/14
s.p(14) =(s.p+1.2)(12)
14sp=12sp+14.4
2sp=14.4
sp=7.2

Is this solution Helpfull? Yes (1) | No (2)  

MOHIT  (7 years ago)

Let the CP be Rs. x per orange
Profit = 20%
SP = [(100+profit)/100]*cp
SP = (120/100)*x ==> 1.2x
Now :-
SP =x+ Rs.1.2
Profit = 40% ==> (140/100)*x
Therefore, we can say
1.40x = x+1.2 or x = Rs. 3
s.p at which he sold= 3*1.2+1.2= 4.8

Is this solution Helpfull? Yes (1) | No (2)  

Manish  (6 years ago)

Let x be the C.P. of an orange.
A/Q - the profit double itself if vendor charges Rs. 1.2 more..
X*20% = 1.2
X = 6
i.e. S.P. = 6 + 20% = 7.2

Is this solution Helpfull? Yes (1) | No (1)  

suryacsr  (6 years ago)

let c.p be 'x' and s.p='y'
orange vendor makes a profit of 20% therefore gain%=20%

gain%=(gain*100)/c.p where gain =s.p-c.p
20=[(y-x)*100]/x

20x=(y-x)*100
2x=10y-10x
12x-10y=0-------(1)


he charges 1.2 extra per orange and he got gain 40%

there s.p=y+1.2
already c.p is assumed as x (above)

again, gain%= (gain*100)/c where gain =s.p-c.p

40=[(y+1.2-x)*100]/x

40x=(y+1.2-x)*100
4x=10y+12-10x
14x-10y=12---------(2)
solve (2) &(1)

14x-10y=12
12x-10y=0
- + -
---------------------
2x=12
therefore x=6 [x=c.p]
originally vendor sold price be x+1.2=7.2

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