Latest Elitmus Aptitude Question SOLUTION: four distinct odd numbers (w^2+x^2) (y^2+z^2) is always divisible by op: 1 4 5 10

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four distinct odd numbers (w^2+x^2) (y^2+z^2) is always divisible by
op:
1
4
5
10

Asked In Elitmus ajay (7 years ago)

Unsolved Read Solution (16)

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Read Solution (16) :

Arashdeep Kaur  (7 years ago)

answer will be 4 because-
1.square of odd number will be an odd number...(w^2=odd) similarly the others.
2. sum off 2 odd numbers will be an even number.(w^2+x^2)=even
3.multiplication of 2 even numbers will be an even number.(w^2+x^2)*(y^2+z^2)
4.One even number can be divisible by 2. so multiplication of 2 even numbers can be divisible by 4.

Is this solution Helpfull? Yes (16) | No (1)  

ajay  (7 years ago)

sorry op;
2
4
5
10
i think 4

Is this solution Helpfull? Yes (5) | No (1)  

Nidhi  (7 years ago)

Ans is 2: Because square of odd number will be odd and sum of two odd number is even
and every even number is divisible by 2

Is this solution Helpfull? Yes (2) | No (1)  

Aqib Azizkhan  (7 years ago)

always divisible by 1

Is this solution Helpfull? Yes (2) | No (3)  

Suresh Kumawat  (7 years ago)

answer is 2 because
1.odd*odd=odd
2.odd+odd=even
3.even*even=even

All even number divisible by 2(not necessary that all even number will be divisible by 4 ,5 and 10)

Is this solution Helpfull? Yes (2) | No   

Vivek Kumar  (7 years ago)

answer is 1
because any number is easily divisible by 1 its not matter that that is even or odd

Is this solution Helpfull? Yes (1) | No (5)  

Sateri J  (7 years ago)

the answer is 4

Is this solution Helpfull? Yes (1) | No   

Archit Agarwal  (7 years ago)

the soln. will be divisible by all..... 1,2 and 4
and not divisible by 5 and 10.

Is this solution Helpfull? Yes (1) | No (1)  

Anil Pokhariyal  (7 years ago)

let put numbers 3,5,7,9
we have (3^2+5^2)*(7^2+9^2)=34*130 i.e. divisible by 10
one more time we can swap values and answer will still be divisible by 10
hence answer is 10
please correct if I am wrong.

Is this solution Helpfull? Yes (1) | No (2)  

Tulika Das  (7 years ago)

addition of two odd numbers give you an even number and multiplication of even number is always even number.So it is divisible by 4

Is this solution Helpfull? Yes | No   

munna kumar  (7 years ago)

on squaring of odd no we will gate an odd no.
i.e- 3*3=9
5*5=25
and we know addition of two odd numbers will give an even no
so,
(w*w+x*x)=even which is divisible by 2
y*y+z*z=even which is also divisible by 2
now
(w*w+x*x)(y*y+z*z) will be devisible by 2*2+4

Is this solution Helpfull? Yes | No   

Atul Kumar Gupta  (7 years ago)

4
summation of two odd squares will leave an even number in two brackets. One two from each bracket will lead to a divisibility by 4.

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TARANG VARSHNEY  (7 years ago)

take w=2,x=3,y=4,z=5
u will get 533 which is divisible by 1 not by 2or 4

Is this solution Helpfull? Yes | No (9)  

KUMAR HARSH  (7 years ago)

all are true

Is this solution Helpfull? Yes | No (4)  

Vikash kumar  (7 years ago)

correct option is 4
odd^2=odd
even+even=even
and even*even=even

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raj  (6 years ago)

Same question they have asked for me one month before.

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