Latest Elitmus Aptitude Question SOLUTION: If w,x,y and z are distinct odd positive integers,then the maximum value of the expression (w^2+x^2)*(y^2+z^2) can be divisible by? a)2 b)3 c)5 d)10

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(#M40156566) ELITMUS Numerical Ability question asked on 26th june 2016 mumbai Keep an EYE

If w,x,y and z are distinct odd positive integers,then the maximum value of the expression (w^2+x^2)*(y^2+z^2) can be divisible by?
a)2 b)3 c)5 d)10

Asked In Elitmus Dhananjay Ghussar (7 years ago)

Unsolved Read Solution (12)

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Read Solution (12) :

vijay  (7 years ago)

ANY ODD NUMBER SQUARE WILL GIVE ODD NUMBER ONLY..
SIMILARLY WEN WE ADD 2 ODD NUMBERS WE WILL GET EVEN NUMBER..
WEN WE MULTIPLY 2 EVEN OWE WILL GET EVEN NUBER..
SO THE RESULT OF THE ABOVE EXPRESSION IS AN EVEN NUMBER ONLY..
HENCE IT IS DIVISIBLE BY 2...

Is this solution Helpfull? Yes (38) | No (4)  

manoj verma  (7 years ago)

Odd*odd=odd
Odd+odd=even
Even*even=even
Eacha and every even no. Is divisible by 2 it is not necessary that every even no. Is divisible by 3,5 or 10 but every even no get divide by 2
So ans is 2...

Is this solution Helpfull? Yes (7) | No   

sameer bhatia  (7 years ago)

answer is 4. any odd number square will give odd number only.
(w^2 + x^2) = odd + odd = even i.e divisible by 2
similarly (y^2 + z^2)= odd + odd = even i.e divisible by 2
now , w^2 + x^2) * (y^2 + z^2) = 2*2 = 4 . so the answer is 4

Is this solution Helpfull? Yes (6) | No (29)  

jitish kumar  (7 years ago)

to maximize the expression...we have to take maximum odd digit positive digits i.e 3,5,7,9
lets say w=3,x=5,y=7,z=9
now, expression = (9+25)*(49+81)= 34*330
which is going to be a multiple of 10
so option d is the correct option

Is this solution Helpfull? Yes (4) | No (15)  

abhishek chaubey  (7 years ago)

only mr. SAMEER BHATIA's answer is correct because if we have both options 2 and 4 then correct answer will be 4. as far as 2 is concerned, if a no is divisible by 4 then its it will be definitely divisble by 2 so more approprite ans is 4 (2 is implicit with it)
moreover multiplication of 2 even no. is always divisible by 4.
so 4 is correct ans

Is this solution Helpfull? Yes (1) | No (5)  

anshul dixit  (7 years ago)

answer is 2
addition of square of two odd numbers= even
therefore even*even= even (which is divisible by 2)

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J PRIYADHARSHINI  (7 years ago)

answer will be 2.

Is this solution Helpfull? Yes (1) | No   

Arashdeep Kaur  (7 years ago)

Answer will be a)divisible by 2
because-
1.square of odd number will be an odd number and then
2.addition of 2 odd number(square of base odd numbers) will give uh an even number.
3.multiplication of 2 even numbers will give uh an even number so it will be divisible by 2.

Is this solution Helpfull? Yes | No (3)  

saiteja D  (7 years ago)

positive integers are 1,3,5,7 and the total is 84 and it is divisible by 3

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bhashkar belwal  (7 years ago)

we have to take the maximum possible value of the expression
so this can be done by only taking values like 3,5,7,9 .
(9+25)* (49+81)= ending with 0;
so it can be divided by 2 , 5 , 10
so in this question , there should be a correction like what is the maximum value or minimum value from which we can divide it

Is this solution Helpfull? Yes | No (1)  

ramakant  (7 years ago)

ans...2
bcz (odd no)^2=odd no.
odd no+odd no=even no..
and even no*even no=even no..
(odd^2+odd^2)*(odd^2+odd^2)
=>(odd+odd)*(odd+odd)
=>even*even
=>even so must be divisible by2

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Shivamsahu  (6 years ago)

As they are using the term 'between' ,we can't count '1',thats why ans is 4999

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