Latest C Aptitude Question SOLUTION: #include void main() { int i; for(i=0;i<10;i++) { if(i<5) continue; else break; printf("%d",i); } }

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(#M40157262) C Programming question general question Keep an EYE

#include
void main()
{
int i;
for(i=0;i<10;i++)
{
if(i<5)
continue;
else
break;
printf("%d",i);
}
}

Asked In C Veena Kumari (7 years ago)

Unsolved Read Solution (13)

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Read Solution (13) :

Pratiksha C Karekar  (7 years ago)

error because standard libraries hasn't defined so as to run the program

Is this solution Helpfull? Yes (3) | No   

Satyendra kumar  (7 years ago)

standard file didn't declare in above program
but after declaration library file
Nothing is printed.

Is this solution Helpfull? Yes (3) | No   

PREM PRASUN  (7 years ago)

without defining library file we can't get output.

Is this solution Helpfull? Yes (2) | No   

kumar prabhat  (7 years ago)

no out put because after break statement it will out of loop it will not read print statement

Is this solution Helpfull? Yes (2) | No   

Kajal Glotra  (7 years ago)

01234 loop get brk ,,, when it reaches 5

Is this solution Helpfull? Yes (1) | No (2)  

Sumeet Jaiswal  (7 years ago)

The output won't return anything.As due to break statement failing the above condition hence it will come out of the loop and won't print anything

Is this solution Helpfull? Yes (1) | No   

ushasri supriya javvaji  (7 years ago)

error!
becz the library file doesn't defined

Is this solution Helpfull? Yes (1) | No   

Honey  (7 years ago)

5
As the loop will terminate whein i will become 5

Is this solution Helpfull? Yes | No (1)  

Harsh Gupra  (7 years ago)

The Answer is 5

Is this solution Helpfull? Yes | No (1)  

Ayan Saha  (7 years ago)

No output.
Reason : For four cases of i , i.e 0 1 2 3 4, continue statement will be encountered, which directs the control to the 'if' condition.

Is this solution Helpfull? Yes | No   

navaneethakrishnan  (7 years ago)

stdio.h library has the definition for the function printf().since here the stdio.h directory is not included.
so the prototype is missing.
Error 'printf' prototype missing
even though if it is included according to the conditions the no output will be printed.

Is this solution Helpfull? Yes | No   

Nemai Layek  (7 years ago)

Notice that printf statement is inside the for loop and there are continue and break statements, therefore for i=0 to i=4 continue will be encountered and for i=5 loop will be terminated because of break statement. Thus the printf will never be excecuted. hence there will be no output for this program.

Is this solution Helpfull? Yes | No   

DAISY DEVA PRIYA S  (6 years ago)

5.After incrementing 4 ,the loop will be terminated.

Is this solution Helpfull? Yes | No   

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