Latest Elitmus Aptitude Question SOLUTION: if x and y are real number. x+y is even? a - x-y id odd b - x^2 - y^2 is odd options are like elitmus

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(#M40157328) ELITMUS Logical Reasoning question problem sloving Keep an EYE

if x and y are real number. x+y is even?
a - x-y id odd
b - x^2 - y^2 is odd

options are like elitmus

Asked In Elitmus amit maurya (7 years ago)

Unsolved Read Solution (11)

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Read Solution (11) :

MUKUL BAGRE  (7 years ago)

x-y=odd.
This means x=even, y=odd or y=even, x=odd.
so x+y=even + odd=odd.

x^2-y^2=odd
now,
x^2-y^2=(x-y)(x+y)
Its only possible when both (x-y) , (x+y) are odd so as to make the product odd.

Take, for example, 5 and 2.
5-2=3;
25-4=21.
So, either of the two statements can answer the question.

Is this solution Helpfull? Yes (20) | No (4)  

Sarvajeet Suman  (7 years ago)

Both options are wrong.

If x+y is even that means that either both x and y are even or both are odd.

suppose
(i) even numbers are 4 & 2
so x-y = 4-2 = 2 i.e. not odd
and 4^2 - 2^2 is also not odd
(ii) odd numbers are 5 & 3
5-3 = 2 is not odd
and 5^2 - 3^2 = 16 i.e. not odd

hence, both the answers are wrong

Is this solution Helpfull? Yes (6) | No (13)  

vivek sharma  (7 years ago)

can be answered by either of the statement
from a) and b) v cud conclude that x is even and y is odd ( use hit and trial)
therefore x+y is always odd hence the possible answer is NO, x+y is not even

Is this solution Helpfull? Yes (2) | No (2)  

Bishal Kumar Shaw  (7 years ago)

It can be answer by using option A : x-y is odd.

Is this solution Helpfull? Yes (2) | No (3)  

shehzad  (7 years ago)

everyone here is getting to the wrong answer by assuming the no. as whole number while the question clearly states that x and y are real numbers

if we take x=7/2 and y= 1/2
then x-y = 7/2-1/2 = 3 which is odd,
but (7/2)^2-(1/2)^2 = 49/4 - 1/4 = 12 which is even
so both statements together draw the conclusion that no. should be taken as whole no. which satisfy the above two conditions i.e. one even and other odd.
hence, both statements are necessary

Is this solution Helpfull? Yes (2) | No (1)  

Abhishek Das  (7 years ago)

Both the options are wrong

Is this solution Helpfull? Yes (1) | No (4)  

sunil kumar patra  (7 years ago)

neither option a nor b is right

Is this solution Helpfull? Yes (1) | No (2)  

sachin pratap singh  (7 years ago)

Both r wrong

Is this solution Helpfull? Yes (1) | No (1)  

Adil khan  (6 years ago)

Hey y are u guys telling both option option are wrong .question is not about option it's about statement it's asking that is x+y is even so both are saying no means both are sufficient alone. Its not about X+y sud be even its just asking yes or no . So in any case ans is sufficient if its ans is maybe then i tll be not sufficient

Is this solution Helpfull? Yes (1) | No   

SHAVALA NANDEESHWARUDU  (7 years ago)

If x+y ,then x and y should be both even or both odd
X-y cannot be odd
x^2-y^2 cannot be odd
So both are wrong

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Manisha Choudhary  (7 years ago)

neither option A nor option B

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