Latest Capgemini Aptitude Question SOLUTION: .In triangle PQR, PQ=6 cm,PR=8 cm and QR=12 cm. Calculate the area of the triangle PQR. A. 23.33 cm2 B. 17.5 cm2 C. 21.33 cm2 D. 28.67 cm2

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.In triangle PQR, PQ=6 cm,PR=8 cm and QR=12 cm. Calculate the area of the triangle PQR.
A. 23.33 cm2 B. 17.5 cm2 C. 21.33 cm2 D. 28.67 cm2

Asked In Capgemini Harjeet Singh (7 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

deblina  (7 years ago)

we know s=(a+b+c+)/2
here a=6cm, b=8cm , c=12cm
therefore s=(6+8+12)/2
=26/2
=13
area of tringle=sqrt [ s (s-a) (s-b) (s-c)
=sqrt [ 13* (13-6) *(13-8)* (13-12)
=sqrt [ 13*7*5*1]
=sqrt [455]
=21.33(ans) [Here sqrt stands for square root]

Is this solution Helpfull? Yes (41) | No (1)  

Nirujogi varaprasad  (7 years ago)

S=(6+8+12)/2
=13
Area=sqrt (s(s-a)*(s-b)*(s-c))
13(13-6)(13-8)(13-12)
=21.33cm2

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virender kumar  (7 years ago)

herons formula so if you calculate its 21.33

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MD RIYAZ UDDIN  (7 years ago)

s=(pq+pr+qr)/2;
area=sqrt of s(s-a)(s-b)(s-c);

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mahaveer kumar dhaker  (7 years ago)

answer c
because
s=a+b+c/2;
s=13
hero formula se

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kamlesh kumar mehta  (7 years ago)

perimeter=(12+8+6)/2=13
Area=sqrt(13*(13-12)*(13-8)*(13-6))=sqrt(13*7*5*1)=21.33

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arpana pandey  (7 years ago)

S=(a+b+c)/2
Area=(s(s-a)(s-b)(s-c))^1/2
S=13
A=sqrt of 455=21.33cm^2

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Hari Balakrishnan  (7 years ago)

s=6+8+12/2=26/2=13
area=sqrt(s(s-a)(s-b)(s-c)
sqrt(13(13-6)*(13-8)*(13-12))
sqrt(455)=21.33

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Shivam Chauhan  (4 years ago)

c 21.33cm,first find semi perimeter and than place it in formula

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