Latest IBM Aptitude Question SOLUTION: Input:Hello world,l Output:9 Input :Hello world,m Output:-1 character 'l' is repeated 3 times we have to return the index value of last 'l' character 'm' is not there so return -1

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(#M40158296) IBM Programming question Java round Keep an EYE

Input:Hello world,l
Output:9
Input :Hello world,m
Output:-1
character 'l' is repeated 3 times we have to return the index value of last 'l'
character 'm' is not there so return -1

Asked In IBM Hari Balakrishnan (7 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

Soundarya Raghavula  (7 years ago)

Can we use scanner class in program???????

Is this solution Helpfull? Yes (5) | No   

  (6 years ago)

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String reverse = " ";
int count = 0;
System.out.println("Enter a string");
String s = sc.nextLine();
for (int i = s.length() - 1; i >= 0; i--) {
reverse = reverse + s.charAt(i);
}
reverse.toString();
System.out.println("enter the character");
char c = sc.next().charAt(0);
for (int i = 0; i < reverse.length(); i++) {
if (c == reverse.charAt(i)) {
if (count == 0) {
int x = s.length() - reverse.indexOf(c);
System.out.println(x);
count++;
}
}}

if (count == 0) {
System.out.println("-1");
}
}
}

Is this solution Helpfull? Yes (4) | No (2)  

raji  (7 years ago)

hi,who have attended the previous drives plzz post java questions and your interview experience.plzz it will be helpful for us a lot.

Is this solution Helpfull? Yes (3) | No   

  (6 years ago)

import java.util.Scanner;
public class HelloWorld{

public static void main(String []args){
Scanner sc=new Scanner(System.in);
String name=sc.nextLine(); //input of a string
String n=sc.nextLine(); //input of the string you need to find
System.out.println(name.lastIndexOf(n));
}
}

Is this solution Helpfull? Yes (3) | No (2)  

sanraj  (6 years ago)

use String class lastIndexOf() method.
eg.
String str = "sanraj todkar";
System.out.println(str.lastIndexOf("a"));

Is this solution Helpfull? Yes (1) | No   

pinkar kumari  (5 years ago)

import java.lang.*;
import java.util.Scanner;
class Abc
{
public static void main(String args[])
{
Scanner in=new Scanner(System.in);
String a;
System.out.println("Enter the String");
a=in.nextLine();
System.out.println("Enter the word:");
char b=in.next().charAt(0);
int count=0;
for(int i=a.length()-1;i>=0;i--)
{
char ch=a.charAt(i);
if(ch==b)
{
System.out.println(i);
count++;
break;
}
}

if(count==0)
System.out.println("-1");

}
}

Is this solution Helpfull? Yes (1) | No   

Ghantasala Naga sirisha   (7 years ago)

hiii hari please share english materials

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