Latest Elitmus Aptitude Question SOLUTION: If v,w,x,y,z are non negative interger each less than 7.then how many distinct combination of (v,w,x,y,z) satisfy v(7^4) + w(7^3)+ x(7^2) + y(7) + z = 151001

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(#M40164389) ELITMUS Numerical Ability question elitmus 16/4/17 Keep an EYE

If v,w,x,y,z are non negative interger each less than 7.then how many distinct combination of (v,w,x,y,z) satisfy

v(7^4) + w(7^3)+ x(7^2) + y(7) + z = 151001

Asked In Elitmus Deepak Bharty (7 years ago)

Unsolved Read Solution (1)

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Read Solution (1) :

Rahul  (6 years ago)

151001
11
4
151001114 = 10 with remainder = 4591

4591
11
3
4591113 = 3 with remainder = 598

598
11
2
598112 = 4 with remainder = 114

114
11
11411 = 10 with remainder = 4

Therefore
151001
=
10
(
11
4
)
+
3
(
11
3
)
+
4
(
11
2
)
+
10
(
11
)
+
4
151001=10(114)+3(113)+4(112)+10(11)+4

i.e., (v,w,x,y,z) is (10,3,4,10,4). These values satisfies given conditions and is one valid option.

Let's analyze if further option available satisfying the given condition. v,w,x,y,z should be less than 11 and greater than zero. The solution we got have v as 10. Suppose v=9. With this, the maximum value possible under the given constraints is
9
(
11
4
)
+
10
(
11
3
)
+
10
(
11
2
)
+
10
(
11
)
+
10
=
146409

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