Latest Elitmus Aptitude Question SOLUTION: if n is between 2 to 50,such that n is divisble by (n-2) ! (factorial). Find the total no. of such numbers.

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(#M40164862) ELITMUS Numerical Ability question number system Keep an EYE

if n is between 2 to 50,such that n is divisble by (n-2) ! (factorial). Find the total no. of such numbers.

Asked In Elitmus aditya kumar (6 years ago)

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sudhansu  (6 years ago)

N is completely divisible by n-2! Then we have to check only n>=n-2! values of n.they are n=2,3,4.

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vijay pandey  (6 years ago)

N is completely divisible by n-2! Then we have to check only n>=n-2! values of n. But n is between 2 to 50....it means that 2

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Binay kumar  (6 years ago)

if we include 2 and 50 then there would be 48-13=35
explanation: 2 and 3 will be divisible by 0 and 1 factorial .
from 4 to 50 all prime no. will not be divisible by (n-2)! and they are like 5,7,11,13,17,19,23,29,31,37,41,43,47 so they are 13 .
hence answer is 48-13=35.

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ehsan  (6 years ago)

n is between 2 to 50 i.e number must be 3 to 49 . total = 47 number
let n=3 , 4 ,5 ,6 & 7
n=3 , (3-2)!/3 1/3 is not divisible
n=4 , (4-2)!/4 2*1/4 is not divisible
n=5 , (5-2)!/5 3*2/5 is not divisible
n=6, (6-2)!/6 4*3*2/6 is divisible
n=7, (7-2)!/7 5*4*3*2/7 is not divisible
after 7 we can see all prime number are not divisible
so number are 3,4,5,7,11,13,17,19,23,29,31,37,41,43,47 total 15
so answer would be 47-15=32

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