Latest IBM Aptitude Question SOLUTION: a printer begin printing at 7:54 am,at the rate of 104 forms per min. another printer begin at 8:20am. printing 117 forms per min. at what time will the two printer have printed th

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a printer begin printing at 7:54 am,at the rate of 104 forms per min. another printer begin at 8:20am. printing 117 forms per min. at what time will the two printer have printed the same number of forms

Asked In IBM meena mourya (11 years ago)

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Read Solution (11) :

suganya  (11 years ago)

diff between 8.20 am ~ 7.54 am = 26 min
here x is time taken to print same no of forms
x*104 + 26*x = x*117
so x=208min
208 min after 8.20 is... 11.48 am

Is this solution Helpfull? Yes (33) | No (15)  

Rajasekar  (10 years ago)

first printer starts at 7.54
2nd printer starts at 8.20
difference is 26 mins
during this 26 mins first printer prints (26*104) = 2704 forms
take the time as 'x' in which both printer prints same no of forms.
so...
117*x = 2704+(104*x)
13x = 2704
x = 208 mins
which is 3 hrs 28 mins...
so 8.20 + 2.28 = 11.44am

Is this solution Helpfull? Yes (32) | No (10)  

KAUSHAL KASHYAP  (10 years ago)

printer p1 starts at 7:54 & p2 starts at 8:20
therefore during this time no. of forms printed by p1=26*104=2704 forms
printer p2 prints 13 forms per min more than p1.(117-104=13)
Now when p2 starts at 8:20 it has to print 2704 more forms than p1 to equal the number of forms printed.
time required to print 2704 more forms than p1= 2704/13=208 mins=3h 28 min
therefore Time will be 8:20+3:28=11:48 am

Is this solution Helpfull? Yes (25) | No   

shivangi singhal  (10 years ago)

Ans. is 11.48 am
suppose two printer have printed the same number of forms after x hrs
then 104x = 117(x-26), (its bcz later printer starts printing after 26 minutes)
now , 117*26 = 117x-104x
3042 = 13x
234 min =x
now add 234min to 7:54 & u will get ur ans. that is 11:48 am

Is this solution Helpfull? Yes (7) | No   

Piya Chatterjee  (11 years ago)

1st printer starts at 7:54am
2nd 8:02am
therefor,difference is 8 mins.
1st printer prints in 8mins=(104*8)=832 forms by which it leads.
2nd printer prints 13forms more than 1st one in 1min.
therefore,the two printers meet each other (832/13)=64 mins after starting of 2nd one.At 9:06am.

Is this solution Helpfull? Yes (5) | No (26)  

Ritesh karn  (11 years ago)

for the first printer no of forms after 8:20= 26*104+104t
for 2nd printer number of forms after it start = 117t

as per condition
117t=26*104+104t
i.e t= (26*104)/13
=208
i.e 3hours 22min

hence at 8:20 + 3hour 20min they will print same number of forms
i.e at 11:44 AM is the answer

Is this solution Helpfull? Yes (2) | No (9)  

saurav  (10 years ago)

11.48
13 MORE PAGES PR MIN BY B,SO (104*26)/13=208 MIN.8.20+3.28=11.48AM

Is this solution Helpfull? Yes (2) | No   

Sarowar Hossain  (9 years ago)

let,total form is printed =x
so, x/104=x/117+26
or, x=(2*104*117)
so the two printer will print same no of form after (2*104*117)/104=234 min
=3hr 54 min
therefore the time is 11:48 am when two printer will print same no of forms.

Is this solution Helpfull? Yes (1) | No   

ASHUTOSH KUMAR  (9 years ago)

let the required time be x minutes from 7.54.
1st printer prints 104x forms nd 2nd printer prints 117*(x-26) forms.
since both are equal, so
104x=117(x-26)
=> x=234 min=3hr 54min
so required time is 7.54am + 3hr 54 min
=11.48 am

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Avinash Singh Rajawat  (9 years ago)

8:20+3:28=11:48 why all add wrong 11:44 If i wrong Tell me.

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vishnu  (9 years ago)

1st printer---->7:57-------------->104 forms
2nd printr---->8:20-------------->117 forms
diffrence in time is -->26 min.
diffrecne in forms is--->13
26*104=2704
2704 divided by 13 =208 min*(i.e 3h.46min)
so,8.20+3.46=11.48

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