Latest Capgemini Aptitude Question SOLUTION: in group of 15 ,7 studied latin 8 studied greek 3 not studied either how many of these both studied latin n greek

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in group of 15 ,7 studied latin 8 studied greek 3 not studied either how many of these both studied latin n greek

Asked In Capgemini janvi sahu (10 years ago)

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YARLAGADDA BALAKRISHNA  (10 years ago)

In a group of 15, 3 have not studied either.
In the group of 12 who have studied at least one, 7 have studied Latin and 8 have studied Greek.
7+8=15, which is 3 larger than 12.
Therefore, 3 students studied both.

Let's check our work:
Not studied either: 3
Studied both: 3
Studied just Latin: 7-3=4
Studied just Greek: 8-3=5
3+3+4+5=15

Is this solution Helpfull? Yes (48) | No (8)  

FAISAL RIZWAN  (10 years ago)

USING VENN DIAGRAM
now we have some equations
(i) A + x + B + 3 = 15
(ii) A + x= 7
(iii) B + x = 8
adding (ii) and (iii), we get
(iv) A + B + 2x = 15
substituting (i) and (iv) we get
A + x + B + 3 = A + B + 2x
subtracting A and B we get
x + 3 = 2x
subtract x to get
x = 3.
3 studied both Latin and Greek

Is this solution Helpfull? Yes (23) | No   

Niveditha  (10 years ago)

3 studied both.
Bcoz 15-3=12 these are the people studied.
7+8=15.
within 12 people how could we get 15 people. so 3 people studied both.

Is this solution Helpfull? Yes (12) | No (1)  

Uday  (10 years ago)

192...
( ) ( ) ( )
8 ways * 6 ways * 4 ways


from 8 members-8 ways
we have 7 now but one in 7 is its spouse-6 ways
now we have 5 but one is spouse of it-4 ways

Is this solution Helpfull? Yes (3) | No (4)  

vikash keshri  (10 years ago)

let 'x' who has both studied latin and greek
then
7+8+3-x=15
x=18-15
x=3
ans 3

Is this solution Helpfull? Yes (1) | No   

meghna  (10 years ago)

First, draw a venn diagram with 2 circles. draw lines in each oval area and a line outside on the right side. These four lines need four numbers.
--
step 1 - place "A" on the first line, "x" on the second line, "B" on the third line and "3" on the outside fourth line.
---
step 2 - now we have some equations
(i) A + x + B + 3 = 15
(ii) A + x= 7
(iii) B + x = 8
adding (ii) and (iii), we get
(iv) A + B + 2x = 15
substituting (i) and (iv) we get
A + x + B + 3 = A + B + 2x
subtracting A and B we get
x + 3 = 2x
subtract x to get
x = 3.
3 studied both Latin and Greek

Is this solution Helpfull? Yes | No   

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