Latest TCS Aptitude Question SOLUTION: There are a certain no of sweets in a box.They are divided in such a way that the person gets 1/4 of the whole get thrice of others.Find the no.of people amongest when the sweets w

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There are a certain no of sweets in a box.They are divided in such a way that the person gets 1/4 of the whole get thrice of others.Find the no.of people amongest when the sweets were distributed.

Asked In TCS mithunprasad (12 years ago)

Solved Harsh Gupta Read Solution (4)

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Read Solution (4) :

Rituraj  (12 years ago)

Qn is not clear.

As per my u8nderstanding, If there are 12 swwets , one person will get 3 sweets and other 9 persons will have 1 each.

So 12 sweets among divided 10 persons.

Many solutions are possible according to this interpretation.

Is this solution Helpfull? Yes (8) | No (2)  

Harsh Gupta  (12 years ago)

Suppose their is x sweets.So First will get x/4.
Remaining amount=x - x/4 = 3x/4.
suppose single man will get y
so 3y = x / 4
y= x / 12.
so 3x / 4 distribute in (3x/4) / (x/12).
=9
So total man = 9 + 1. =10.

Is this solution Helpfull? Yes (3) | No   

bharat jaiswal  (12 years ago)

three possibility only
if 1 person get 1/4 of whole then 9 person will get 1/12 of sweet so total 10 person
if 2 person get 1/4 of whole then 6 person will get 1/12 of sweet so total 8 person
if 3 person get 1/4 of whole then 3 person will get 1/12 of sweet so total 6 person will get sweet
So question should be clear enough to find single answer

Is this solution Helpfull? Yes (2) | No (1)  

sachin suryvamshi  (12 years ago)

give a person with 1/4 has three times as others so consider him as 3x sweets
others contain x seats each
now 3x=1/4 x=1/12
now as we got prob then
1/4+n(1/12)=1
we get n=9
and including d person containg 1/4 share we get 9+1 persons=10 persons

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