Latest TCS Aptitude Question SOLUTION: An equation of the form 4x+6y-2z=32 . Find the difference between x intercept and z intercept?

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An equation of the form 4x+6y-2z=32 . Find the difference between x intercept and z intercept?

Asked In TCS Utsav Mukherjee (12 years ago)

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suchandra raavi  (12 years ago)

To find X intercept, keep other 2 axis 0. That is y=0 and z=0. Equation becomes 4x = 32 or x = 8. Similarly to find Z intercept keep y=0 and x=0. Equation becomes -2z = 32 or z = -16. Difference is clearly 8-(-16) = 24.

Is this solution Helpfull? Yes (36) | No (7)  

Dineshlal  (12 years ago)

x intercept is (8,0,0)
z intercept is (0,0,-6)
distance b/w x & z intercept is (((8-0)^2)+((0-0)^2)+((0-(-16))^2)^(1/2))
=8((5)^(1/2))

Is this solution Helpfull? Yes (8) | No (2)  

virendra  (12 years ago)

x-intercept: Set .


(8,0,0)
.
.
.


z-intercept: Set


(0,0,-16)
.
.
.
The difference=
x-z= 8 -(-16)= 24

Is this solution Helpfull? Yes (4) | No (4)  

Ambika Prasad Tiwari  (12 years ago)

for x intercet put y=0,z=0 so x=32/4=8 ie (8,0,0)
similarly z=-8ie (0,0,-6)
so distance is sqrt(8^2+0^2+(-6)^2)=10

Is this solution Helpfull? Yes (2) | No (7)  

Amandeep  (12 years ago)

intercept is always positive, as intercept is the distance from the origin to the point of intersection of the line or plane with the axis and also distance can't be negative. so

intercept of the x-axis is---|32/4|=8
and
intercept of the z-axis is---|32/-2|=16

so the difference is 16-8=8 or 8-16=-8 and if both options are given then 8 will be the answer.

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