Latest TCS Aptitude Question SOLUTION: There are two water tanks A and B , A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10,20,40,80,160 .. in tank B. (At the end of first hour, B has 10 litres, second hour it has 20, and so on). If tank B is 1/8 filled after 23 hours, what is the total duration required to fill it completely? 27 hours 25 hours 26 hours 3 hours

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(#M40002322) TCS aptitude question TCS Fresher Job Placement Paper : 14 Aug 2011 Keep an EYE

There are two water tanks A and B , A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10,20,40,80,160 .. in tank B. (At the end of first hour, B has 10 litres, second hour it has 20, and so on). If tank B is 1/8 filled after 23 hours, what is the total duration required to fill it completely?
27 hours
25 hours
26 hours
3 hours

Asked In TCS Submited By-- Aashu (1 year ago)

Puzzle Status: Unsolved

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soumya goyal  (1 year ago)

rate of A = 2times of B
till now 23 hrs have been completed and tank B is 1/8 filled.
hence in next one hr 2 times of it would get filled...i.e. (1/8)*2=1/4
after another one hr=(1/4)*2=1/2
another one hr=(1/2)*2=1 (fully filled)
it required extra 3 hrs.
hence ans is 23+3=26 hrs.
TIP: try to make the fraction part 1 by multiplying with the factor given in the ques. no of times u multiplied to make it no= no of extra hrs.

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athushi  (1 year ago)

1/8 - 23
1/4 - 24
1/2 - 25
1 - 26
Ans: 26

Everytime the water filled double..

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Jayatu Bhowmick  (1 year ago)

1/8=1/2^3
1/8 filled after 23 hours
So it will totally filled up the tank 23+3=26 hours

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Arpit Mathur  (1 year ago)

the tank fills double in every 1 hour. so, if in 23 hours the tank is 1/8 filled.....
therefore in 24hrs== 2*1/8=1/4
25hr= 1/2
26th hour= 1...therefore the tank is full

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(#M40000712) TCS MATHS PUZZLE Keep an EYE

There are two water tanks A and B, A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160... in tank B.( At the end of first hour, B has 10 litres , second hour it has 20, and so on). If tank B is 1/32 filled after 21 hours, what is the total duration required to fill it completely?

a) 26 hrs (b) 25 hrs (c) 5 hrs (d) 27 hrs

Asked In TCS Submited By-- Rajeev Singh (2 year ago)

Puzzle Status: Solved     By »» Sivabharathi

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Sivabharathi  (2 year ago)

Here the tank B is considered.. Its capacity is doubling after each hour(10,20,40,80,160,....).If it gets filled 1/32 after 21 hrs, then it will be
1/16 after 22 hrs and
1/8 after 23 hrs
1/4 after 24 hrs
1/2 after 25 hrs
and 1 after 26 hrs..
hence the total duration is 26 hrs

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YadeeshKumar  (2 year ago)

ans is a)26 hrs
in 22nd hour it fills 1/16
in 23rd hour it fills 1/8
in 24th hour it fills 1/4
in 25th hour it fills 1/2
in 26th hour it fills 1

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ramya  (2 year ago)

if 1/32 in 21 hrs means then
1/16 in 22 hrs then
1/8 in 23 hrs then
1/4 in 24 hrs then
1/2 in 25 hrs then
1/1 in 26 hrs and answer is 26 hrs

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anuj  (2 year ago)

my dear friend ur asked questions are already solved in prev asked sections just look it .. get verrified

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suneil  (2 year ago)

26 hr. At the end of first hour, B has 10 litres , second hour it has 20, and so on). If tank B is 1/32 filled after 21 hours, then 1/16 in the next hr i.e 22, 1/8 in 23, 1/4 in 24, 1/2 in 25 and 1( fully ) in 26 hours.

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sai naresh  (2 year ago)

1/32th in 21
1/16 in 22
.
.
.
. 25hr

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manjusha  (2 year ago)

5+21=26
ans is 26

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(#M40001739) TCS MATHS PUZZLE question 2010 Keep an EYE

There are two water tanks A and B, A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160... in tank B.( At the end of first hour, B has 10 litres , second hour it has 20, and so on). If tank B is 1/32 filled after 21 hours, what is the total duration required to fill it completely?
(a) 26 hrs (b) 25 hrs (c) 5 hrs (d) 27 hrs

Asked In tcs Submited By-- UN (1 year ago)

Puzzle Status: Solved     By »» DIPIN

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DIPIN  (1 year ago)

There are two water tanks A and B, A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160... in tank B.( At the end of first hour, B has 10 litres , second hour it has 20, and so on). If tank B is 1/32 filled after 21 hours, .
then tank B is 1/16 filled after 22 hours
tank B is 1/8 filled after 23 hours
tank B is 1/4 filled after 24 hours
tank B is 1/2 filled after 25 hours
tank B is fuuly filled after 26 hours

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Pritam  (1 year ago)

21+log32=21+log(2^5)=26

Is this solution Helpfull? Yes (5) | No (9)  

(#M40001563) TCS MATHS PUZZLE latest question Keep an EYE

) There are two water tanks A and B, A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160... in tank B.( At the end of first hour, B has 10 litres , second hour it has 20, and so on). If tank B is 1/32 filled after 21 hours, what is the total duration required to fill it completely?

a) 26 hrs
b) 25 hrs
c) 5 hrs
d) 27 hrs

Asked In tcs Submited By-- Aditi Sharma (1 year ago)

Puzzle Status: Unsolved

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(#M40001615) TCS MATHS PUZZLE latest question Keep an EYE

There are two water tanks A and B, A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160... in tank B. (At the end of first hour, B has 10 litres , second hour it has 20, and so on). If tank B is 1/16 filled after 4 hours, what is the total duration required to fill it completely?

a) 8hrs b) 25 hrs c) 5 hrs d) 27 hrs

Asked In tcs Submited By-- UN (1 year ago)

Puzzle Status: Unsolved

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Shivam Gupta  (1 year ago)

Ans is a.)8hrs
let total duration be x
so x/16 in 4hrs
x/16*2 in 5hrs ( we are multiplying by 2 bcoz tank B gets doubled)
x/8*2 in 6hrs
x/4*2 in 7hrs
x/2*2 in 8hrs
we get x now which is total duration.

Is this solution Helpfull? Yes (4) | No (1)