Latest TCS Aptitude Question SOLUTION: Ram and Sakil run a race of 2000 meters. First, Ram gives Sakil a start of 200 meters and beats him by one minute. Next, Ram gives Sakil a start of 6 minutes and is beaten by 1000

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(#M40024360) TCS Numerical Ability question Keep an EYE

Ram and Sakil run a race of 2000 meters. First, Ram gives Sakil a start of 200 meters and beats him by one minute. Next, Ram gives Sakil a start of 6 minutes and is beaten by 1000 meters. Find the time in minutes in which Ram and Sakil can run the races separately.
option
a) 8,10
b) 10,18
c) 12,18
d) 10,12

Asked In TCS sridurgauppalapati (10 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

PRANAV PANDEY  (10 years ago)

1 scenario. Ram covers 200m in 1 min so speed=200m/min.
2. scenario. Sakil covers 1000m in 6 min so speed =500/3 m/min.
now time taken by ram=2000/200=10min.
time taken by sakil = 2000/(500/3)=12min
so ans is 10,12

Is this solution Helpfull? Yes (24) | No (28)  

mohit ranjan basak  (10 years ago)

ram travel 2000m then sakil travel 1800-v.[v=velocity of sakil]
ram travel 1000m then sakil travel 2000-6v.
i.e.2000/1000=1800-v/2000-6v
v=200m/min
time taken by sakil=2000/200=10min
similrly time taken by ram=8min

Is this solution Helpfull? Yes (23) | No (14)  

shantanu jawale  (9 years ago)

Let x and y are the speeds of Ram and Shakil.. Then by problem we got following equation
2000/x=(1800/y)-1
1000/X=(2000/y)-6
solve equation 1 and 2, we get x=250 and y=200
Therefore, Time taken by Ram and Shakilk to complete a race of 2000m is 8 min and 10 Min

Is this solution Helpfull? Yes (9) | No (2)  

ramesh  (9 years ago)

let time taken by ram for 2000m be x, therefore time taken by sakil for 1800m(as ram gave head start of 200m) is (x+1)
time taken by sakil for 2000m is....
((2000*(x+1))/1800)= (10(x+1)/9)
when sakil beats ram by 1000m when 6 minutes of head start is given..it means ram has already travelled 1000m
so time taken by ram will be half of time of 2000m = (x/2)
time taken by sakil to complete race when a head start
of 6 minutes is given is.......((10(x+1)/9)-6)
..we know that time taken by ram for 1000m is equal to time taken by sakil to complete race when 6 min of head start is given..
i.e. (x/2)=((10(x+1)/9)-6)
=> ((x/2)+6)=((10x/9)+(10/9))
=> (6-(10/9))=((10x/9)-(x/2))
=> x=8
therefore, time taken by ram (x)=8
and time taken by sakil = (10(x+1)/9) = (10*9/9) = 10
ANS: 8,10

Is this solution Helpfull? Yes (5) | No (1)  

anubhav gupta  (10 years ago)

answer is 8,10

Is this solution Helpfull? Yes (2) | No (3)  

babu rao ganpat rao apte  (10 years ago)

sumbody explain this

Is this solution Helpfull? Yes (1) | No   

pritam kundu  (10 years ago)

ram=709sec
sakil=698 sec

Is this solution Helpfull? Yes | No (12)  

Chinnu Naseer  (9 years ago)

which answer is correct?? option A or D????

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