Latest TCS Aptitude Question SOLUTION: An athlete decides to run the same distance in 1/4th less time that she usually took. By how percent will she have to increase her average speed

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An athlete decides to run the same distance in 1/4th less time that she usually took. By how percent will she have to increase her average speed

Asked In TCS preethi poosa (12 years ago)

Solved siddharth pandey Read Solution (4)

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Read Solution (4) :

Ambika Prasad Tiwari  (12 years ago)

let be the original time s1,s2 be the two speeds
now new time=t-t/4=3t/4
now distance remaining same
t*s1=(3t/4)*s2
s2=4/3s1=(1+1/3)s1
so the athlete should increase his speed by one-third

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siddharth pandey  (12 years ago)

let original speed be s1 and time be t1
then s1=d/t1 ---eqn 1
and according to ques
new speed be s2 and time given is 3t1/4
therefore s2=d/(3t1/4) -----eqn 2
dividing eqn 2 by eqn 1
s2=4s1/3
increased speed = 4s1/3-s1
=1s1/3
percent increase=[(1s1/3)/s1]*100
=33.33%

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yumnam girish  (12 years ago)

ane is 33.33%

Is this solution Helpfull? Yes (5) | No (6)  

Satyaveer Singh  (8 years ago)

Let orginal time is 4 min. and now new time is 3 min acc. to question

so increase speed is = (d/4-d/3) / (d/4) = d/3 its means 33.33%

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