Latest TCS Aptitude Question SOLUTION: 4 lines are parallel to the base of the triangle ,if the lines divide the triangle into 5 equal spaces . If the area of the largest space is 27sqcm what is the total area of triang

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4 lines are parallel to the base of the triangle ,if the lines divide the triangle into 5 equal spaces . If the area of the largest space is 27sqcm what is the total area of triangle?

Asked In TCS Nikhil (10 years ago)

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nk gour  (10 years ago)

in triangle largest space will make 9 small triangle inside it which each has area of 3 sqcm. such that in whole triangle there are 25 smalls triangle
25*3=75sqcm (area of triangle)
ans. 75 sqcm

Is this solution Helpfull? Yes (20) | No (2)  

Anju Giri  (10 years ago)

i think that dividing in 5 equal spaces means height is divided into 5 equal parts..bcz area of the 5 parts can never be equal....if we consider 27 as the difference of 2 triangle's area whose height is in the ratio 4:5,then the total area will be 75.

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Rajat Gupta  (10 years ago)

27 * 5 =135sqcm as triangle is divided into 5 equal spaces

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Rajat Gupta  (10 years ago)

(27*5)/2= 67.5sqcm

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sourav dutta  (10 years ago)

162..because 5lines divides the triangle into 6 equal spaces with area of each=27 sqcm

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amit   (10 years ago)

75...............

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SHIVASHISH BHARDUAJ  (10 years ago)

its 9*3+7*3+5*3+3*3+1*3=75

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Bhaswati Chatterjee  (9 years ago)

height h is divided in 5 parts. let h/5=l. if a line parallel to base cuts a triangle, it forms a trapezoid. Area of trapezoid is 1/2*height*(base1+base2). For the largest trapezoid i.e. the one associated with the base of triangle, base1= base of triangle. height=l. for base2, if we draw a perpendicular from every intersection point of the parallel lines and arms of triangle, we get the base divided in 10 equal parts i.e. every part is equal to a/10. So the length of base2 must be equal to (a- 2*a/10)=4*a/5. so the area of trapezoid is 1/2*l*(a+4a/5)=27. Solving a=30/l. So the area of triangle= 1/2*5l*30/l=75sqcm.

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