Latest HCL Aptitude Question SOLUTION: 5)One person start from his home towards college which is 53 km far away. Another person started from college towards home after an hour. the speed of first one is 4kmph and the se

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5)One person start from his home towards college which is 53 km far away. Another person
started from college towards home after an hour. the speed of first one is 4kmph and the second
one is 3 kmph. Then, what is the distance from home to their meeting point?
AND:21 km.

6)3 machines can complete the work in 4,5, and 6 hours respectively. due to power failures they
did the work alternatively. Then what is time taken to complete the work?
ANS:9/20
pls help

Asked In HCL lekha (12 years ago)

Unsolved Read Solution (6)

Is this Puzzle helpful?   (12)   (4) Submit Your Solution Time Distance and Speed

Read Solution (6) :

Atul  (12 years ago)

Ans is 32 kms from home and 21 kms from college.
If s is distance from home where they met , then
s/4 = 1+ (53-s)/3
solving it, we get s= 32 kms.
The first person travelled 32 kms in 8 hrs @ 4kmph and
The 2nd person travelled 21 kms in 7 hrs @ 3kmph.

Is this solution Helpfull? Yes (22) | No (1)  

dular chandran  (12 years ago)

total distance=53km,late meeting point from home=x,then remaining distance=53-x.
here given in question another person started from college after an hour, so one hour more then first person have to go. so T1=T2+1.
T1=X/4
T2=((53-X)/3)+1
T1=T2+1(time taken by both person for miiting must be equal)
x/4=(53-x)3+1
x/4=56-x/3
7x=224
x=32
then they will meet at 53-x or 53-32km it mean 21km from home

Is this solution Helpfull? Yes (11) | No (6)  

Atul  (12 years ago)

3 machines can complete the work in 4,5, and 6 hours respectively. due to power failures they did the work alternatively.
Work done in 1st hr = 15/60
Work done in 2nd hr = 12/60

Work done in 3rd hr = 10/60

Work done in 4th hr = 15/60
Balance work = 1-(15+12+10+15)/60 =1-52/60 = 8/60
Time taken for 8/60 work by 2nd machine = (8/60)*(60/12)=8/12 hrs = 2/3 hrs =40 mins
so total time taken = 4 hrs 40 mins

Is this solution Helpfull? Yes (10) | No (7)  

Atul  (12 years ago)

Ans is 32 kms from home and 21 kms from college.
If s is distance from home where they met , then
s/4 = 1+ (53-s)/4
solving it, we get s= 32 kms.
The first person travelled 32 kms in 8 hrs @ 4kmph and
The 2nd person travelled 21 kms in 7 hrs @ 3kmph.

Is this solution Helpfull? Yes (4) | No   

ashish ranjan  (7 years ago)

5) after 1hr B started so A covers 4km
so distance have to cover by A and B is (53-4) = 49 km only
and every hr both cover (3+4) = 7km so after 7 hr they meet each other

now the distance from home to their meeting point = (7*4)km + remaining 4km = 32km

Is this solution Helpfull? Yes (1) | No   

garima Misra  (7 years ago)

In first three hours, work done=(1/4)+(1/5)+(1/6)=37/60
remaining work=1-(37/60)=23/60
on the next fourth hour=1/4
now the remaining work will be=4/15
time is taken by the second machine=1/(1/5) * (4/15)
Hence total time=5 hour 20 min

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