Latest TCS Aptitude Question SOLUTION: By using 1,2,3,4,5,how many 5 digit no. can be formed which is divisible by 4,repetation of no. is allowed??

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(#M40002691) TCS Numerical Ability question tcs Keep an EYE

By using 1,2,3,4,5,how many 5 digit no. can be formed which is divisible by 4,repetation of no. is allowed??

Solution

for first 3 places we have 5*5*5=125 combinations
next 2 possibilities are 12,24,32,44,52
so 125*5=625 numbers
This answer is given by SANDEEP REDDY M and is correct answer

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Asked In TCS purvi (12 years ago)

Solved Read Solution (3)

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Read Solution (3) :

Akash Sharma  (12 years ago)

answer is 5^4 = 625

Is this solution Helpfull? Yes (7) | No (15)  

kiran  (11 years ago)

step 1->the no divisible by only if it divisible by last 2 digit of no
step 2->there for in this example that last 2 digit no are 12,24,32,44,52 ie total 5
step 3-> - - - 1 2, - - - 24,same take other.....
step 4--> use combination formula ncr=n!/r!(n-r)!
step 5-->3 place remaining & available no 5 ie n=5
step 6-->5c1 * 5c1 * 5c1=125
step 7--->125*5=625

Is this solution Helpfull? Yes (4) | No (1)  

Stuti Kaushal  (12 years ago)

units place can be filled by 2 ,4 as no. is to b divisible by 4
since repitition of digits is allowed,
hence no of ways to form 5 digit no. are 2*5*5*5*5 = 1250

Is this solution Helpfull? Yes (1) | No (22)  

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